Python pandas splitting text and numbers in dataframe










0















I have a dataframe df1 with column name Acc Number as the first column and the data looks like:



Acc Number
ASC100.1
MJT122
ASC120.4
XTY111


I need to make a new dataframe df2 that will have two columns first having the text part and the second having the numbers so the desired output is:



Text Number 
ASC 100.1
MJT 122
ASC 100.4
XTY 111


How would I go about doing this?



Thanks!










share|improve this question


























    0















    I have a dataframe df1 with column name Acc Number as the first column and the data looks like:



    Acc Number
    ASC100.1
    MJT122
    ASC120.4
    XTY111


    I need to make a new dataframe df2 that will have two columns first having the text part and the second having the numbers so the desired output is:



    Text Number 
    ASC 100.1
    MJT 122
    ASC 100.4
    XTY 111


    How would I go about doing this?



    Thanks!










    share|improve this question
























      0












      0








      0








      I have a dataframe df1 with column name Acc Number as the first column and the data looks like:



      Acc Number
      ASC100.1
      MJT122
      ASC120.4
      XTY111


      I need to make a new dataframe df2 that will have two columns first having the text part and the second having the numbers so the desired output is:



      Text Number 
      ASC 100.1
      MJT 122
      ASC 100.4
      XTY 111


      How would I go about doing this?



      Thanks!










      share|improve this question














      I have a dataframe df1 with column name Acc Number as the first column and the data looks like:



      Acc Number
      ASC100.1
      MJT122
      ASC120.4
      XTY111


      I need to make a new dataframe df2 that will have two columns first having the text part and the second having the numbers so the desired output is:



      Text Number 
      ASC 100.1
      MJT 122
      ASC 100.4
      XTY 111


      How would I go about doing this?



      Thanks!







      python pandas dataframe






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 13 '18 at 23:14









      AndyAndy

      537




      537






















          1 Answer
          1






          active

          oldest

          votes


















          1














          You could do something like this:



          import pandas as pd

          data = ['ASC100.1',
          'MJT122',
          'ASC120.4',
          'XTY111']

          df = pd.DataFrame(data=data, columns=['col'])

          result = df.col.str.extract('([a-zA-Z]+)([^a-zA-Z]+)', expand=True)
          result.columns = ['Text', 'Number']
          print(result)


          Output



           Text Number
          0 ASC 100.1
          1 MJT 122
          2 ASC 120.4
          3 XTY 111


          The pattern ([a-zA-Z]+)([^a-zA-Z]+) means match a group of letters: ([a-zA-Z]+) followed by a group of non letters: ([^a-zA-Z]+). A safer alternative will be to use the following regex: ([a-zA-Z]+)(d+.?d+) assuming the numbers can only have at most one point.



          Further



          1. The documentation on regex in Python.

          2. The documentation on extract.





          share|improve this answer

























          • Thanks Daniel, the str.extract worked, why would the regex be a safer option?

            – Andy
            Nov 13 '18 at 23:28











          • Because it will match only and only numbers with a possible point among them.

            – Daniel Mesejo
            Nov 13 '18 at 23:30










          Your Answer






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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You could do something like this:



          import pandas as pd

          data = ['ASC100.1',
          'MJT122',
          'ASC120.4',
          'XTY111']

          df = pd.DataFrame(data=data, columns=['col'])

          result = df.col.str.extract('([a-zA-Z]+)([^a-zA-Z]+)', expand=True)
          result.columns = ['Text', 'Number']
          print(result)


          Output



           Text Number
          0 ASC 100.1
          1 MJT 122
          2 ASC 120.4
          3 XTY 111


          The pattern ([a-zA-Z]+)([^a-zA-Z]+) means match a group of letters: ([a-zA-Z]+) followed by a group of non letters: ([^a-zA-Z]+). A safer alternative will be to use the following regex: ([a-zA-Z]+)(d+.?d+) assuming the numbers can only have at most one point.



          Further



          1. The documentation on regex in Python.

          2. The documentation on extract.





          share|improve this answer

























          • Thanks Daniel, the str.extract worked, why would the regex be a safer option?

            – Andy
            Nov 13 '18 at 23:28











          • Because it will match only and only numbers with a possible point among them.

            – Daniel Mesejo
            Nov 13 '18 at 23:30















          1














          You could do something like this:



          import pandas as pd

          data = ['ASC100.1',
          'MJT122',
          'ASC120.4',
          'XTY111']

          df = pd.DataFrame(data=data, columns=['col'])

          result = df.col.str.extract('([a-zA-Z]+)([^a-zA-Z]+)', expand=True)
          result.columns = ['Text', 'Number']
          print(result)


          Output



           Text Number
          0 ASC 100.1
          1 MJT 122
          2 ASC 120.4
          3 XTY 111


          The pattern ([a-zA-Z]+)([^a-zA-Z]+) means match a group of letters: ([a-zA-Z]+) followed by a group of non letters: ([^a-zA-Z]+). A safer alternative will be to use the following regex: ([a-zA-Z]+)(d+.?d+) assuming the numbers can only have at most one point.



          Further



          1. The documentation on regex in Python.

          2. The documentation on extract.





          share|improve this answer

























          • Thanks Daniel, the str.extract worked, why would the regex be a safer option?

            – Andy
            Nov 13 '18 at 23:28











          • Because it will match only and only numbers with a possible point among them.

            – Daniel Mesejo
            Nov 13 '18 at 23:30













          1












          1








          1







          You could do something like this:



          import pandas as pd

          data = ['ASC100.1',
          'MJT122',
          'ASC120.4',
          'XTY111']

          df = pd.DataFrame(data=data, columns=['col'])

          result = df.col.str.extract('([a-zA-Z]+)([^a-zA-Z]+)', expand=True)
          result.columns = ['Text', 'Number']
          print(result)


          Output



           Text Number
          0 ASC 100.1
          1 MJT 122
          2 ASC 120.4
          3 XTY 111


          The pattern ([a-zA-Z]+)([^a-zA-Z]+) means match a group of letters: ([a-zA-Z]+) followed by a group of non letters: ([^a-zA-Z]+). A safer alternative will be to use the following regex: ([a-zA-Z]+)(d+.?d+) assuming the numbers can only have at most one point.



          Further



          1. The documentation on regex in Python.

          2. The documentation on extract.





          share|improve this answer















          You could do something like this:



          import pandas as pd

          data = ['ASC100.1',
          'MJT122',
          'ASC120.4',
          'XTY111']

          df = pd.DataFrame(data=data, columns=['col'])

          result = df.col.str.extract('([a-zA-Z]+)([^a-zA-Z]+)', expand=True)
          result.columns = ['Text', 'Number']
          print(result)


          Output



           Text Number
          0 ASC 100.1
          1 MJT 122
          2 ASC 120.4
          3 XTY 111


          The pattern ([a-zA-Z]+)([^a-zA-Z]+) means match a group of letters: ([a-zA-Z]+) followed by a group of non letters: ([^a-zA-Z]+). A safer alternative will be to use the following regex: ([a-zA-Z]+)(d+.?d+) assuming the numbers can only have at most one point.



          Further



          1. The documentation on regex in Python.

          2. The documentation on extract.






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 13 '18 at 23:29

























          answered Nov 13 '18 at 23:20









          Daniel MesejoDaniel Mesejo

          16.9k21430




          16.9k21430












          • Thanks Daniel, the str.extract worked, why would the regex be a safer option?

            – Andy
            Nov 13 '18 at 23:28











          • Because it will match only and only numbers with a possible point among them.

            – Daniel Mesejo
            Nov 13 '18 at 23:30

















          • Thanks Daniel, the str.extract worked, why would the regex be a safer option?

            – Andy
            Nov 13 '18 at 23:28











          • Because it will match only and only numbers with a possible point among them.

            – Daniel Mesejo
            Nov 13 '18 at 23:30
















          Thanks Daniel, the str.extract worked, why would the regex be a safer option?

          – Andy
          Nov 13 '18 at 23:28





          Thanks Daniel, the str.extract worked, why would the regex be a safer option?

          – Andy
          Nov 13 '18 at 23:28













          Because it will match only and only numbers with a possible point among them.

          – Daniel Mesejo
          Nov 13 '18 at 23:30





          Because it will match only and only numbers with a possible point among them.

          – Daniel Mesejo
          Nov 13 '18 at 23:30

















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