How to remove brackets from JSON in Python?
1
I am using json.dumps to load lists of dictionaries into a JSON object. My output resembles this:
[
"MetaData": ,
"SRData":
"ListOfLa311DeadAnimalRemoval":
"DeadAnimalRemoval": [
"DACItemCount": "0",
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Name": "070920151119458601",
"Type": "Dead Animal Removal"
,
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Type": "Dead Animal Removal"
]
,
"ReasonCode": "",
"ResolutionCode": "A",
"SRNumber": "1-20979881"
]
How do I successfully remove the brackets at the beginning and end of the JSON object?
Code that appends dictionaries and lists:
dL311 = dict()
dL311.setdefault("DeadAnimalRemoval", l311)
dResult.setdefault("ListOfLa311DeadAnimalRemoval",dL311)
#Ends of adding additional itmes ****************************************
lResults.append("MetaData": , "SRData": dResult)
ii = ii + 1
print(json.dumps(lResults, sort_keys=True, indent=4))
python json dictionary
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
add a comment |
1
I am using json.dumps to load lists of dictionaries into a JSON object. My output resembles this:
[
"MetaData": ,
"SRData":
"ListOfLa311DeadAnimalRemoval":
"DeadAnimalRemoval": [
"DACItemCount": "0",
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Name": "070920151119458601",
"Type": "Dead Animal Removal"
,
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Type": "Dead Animal Removal"
]
,
"ReasonCode": "",
"ResolutionCode": "A",
"SRNumber": "1-20979881"
]
How do I successfully remove the brackets at the beginning and end of the JSON object?
Code that appends dictionaries and lists:
dL311 = dict()
dL311.setdefault("DeadAnimalRemoval", l311)
dResult.setdefault("ListOfLa311DeadAnimalRemoval",dL311)
#Ends of adding additional itmes ****************************************
lResults.append("MetaData": , "SRData": dResult)
ii = ii + 1
print(json.dumps(lResults, sort_keys=True, indent=4))
python json dictionary
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
You may not really want to do the because it may force other code that deals with the result have to check whether it is a list or dictionary (or assume it's one or the other and usetry/exceptin handle the situation when the assumption is incorrect.
– martineau
Jul 27 '15 at 1:21
You don't just "remove brackets", you need to recognize what exactly they represent. Your json represents an array of objects. To think of it any other way is just downright wrong.
– Jeff Mercado
Jul 27 '15 at 1:21
add a comment |
1
1
1
I am using json.dumps to load lists of dictionaries into a JSON object. My output resembles this:
[
"MetaData": ,
"SRData":
"ListOfLa311DeadAnimalRemoval":
"DeadAnimalRemoval": [
"DACItemCount": "0",
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Name": "070920151119458601",
"Type": "Dead Animal Removal"
,
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Type": "Dead Animal Removal"
]
,
"ReasonCode": "",
"ResolutionCode": "A",
"SRNumber": "1-20979881"
]
How do I successfully remove the brackets at the beginning and end of the JSON object?
Code that appends dictionaries and lists:
dL311 = dict()
dL311.setdefault("DeadAnimalRemoval", l311)
dResult.setdefault("ListOfLa311DeadAnimalRemoval",dL311)
#Ends of adding additional itmes ****************************************
lResults.append("MetaData": , "SRData": dResult)
ii = ii + 1
print(json.dumps(lResults, sort_keys=True, indent=4))
python json dictionary
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
I am using json.dumps to load lists of dictionaries into a JSON object. My output resembles this:
[
"MetaData": ,
"SRData":
"ListOfLa311DeadAnimalRemoval":
"DeadAnimalRemoval": [
"DACItemCount": "0",
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Name": "070920151119458601",
"Type": "Dead Animal Removal"
,
"DACType": " ",
"DriverFirstName": "SA",
"DriverLastName": "Aguilar",
"LastUpdatedBy": "SANSTAR1",
"Type": "Dead Animal Removal"
]
,
"ReasonCode": "",
"ResolutionCode": "A",
"SRNumber": "1-20979881"
]
How do I successfully remove the brackets at the beginning and end of the JSON object?
Code that appends dictionaries and lists:
dL311 = dict()
dL311.setdefault("DeadAnimalRemoval", l311)
dResult.setdefault("ListOfLa311DeadAnimalRemoval",dL311)
#Ends of adding additional itmes ****************************************
lResults.append("MetaData": , "SRData": dResult)
ii = ii + 1
print(json.dumps(lResults, sort_keys=True, indent=4))
python json dictionary
python json dictionary
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
edited Nov 11 '16 at 14:53
fragilewindows
1,1931920
1,1931920
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
asked Jul 27 '15 at 1:05
geoffreyGISgeoffreyGIS
83211
83211
You may not really want to do the because it may force other code that deals with the result have to check whether it is a list or dictionary (or assume it's one or the other and usetry/exceptin handle the situation when the assumption is incorrect.
– martineau
Jul 27 '15 at 1:21
You don't just "remove brackets", you need to recognize what exactly they represent. Your json represents an array of objects. To think of it any other way is just downright wrong.
– Jeff Mercado
Jul 27 '15 at 1:21
add a comment |
You may not really want to do the because it may force other code that deals with the result have to check whether it is a list or dictionary (or assume it's one or the other and usetry/exceptin handle the situation when the assumption is incorrect.
– martineau
Jul 27 '15 at 1:21
You don't just "remove brackets", you need to recognize what exactly they represent. Your json represents an array of objects. To think of it any other way is just downright wrong.
– Jeff Mercado
Jul 27 '15 at 1:21
You may not really want to do the because it may force other code that deals with the result have to check whether it is a list or dictionary (or assume it's one or the other and use
try/except in handle the situation when the assumption is incorrect.– martineau
Jul 27 '15 at 1:21
You may not really want to do the because it may force other code that deals with the result have to check whether it is a list or dictionary (or assume it's one or the other and use
try/except in handle the situation when the assumption is incorrect.– martineau
Jul 27 '15 at 1:21
You don't just "remove brackets", you need to recognize what exactly they represent. Your json represents an array of objects. To think of it any other way is just downright wrong.
– Jeff Mercado
Jul 27 '15 at 1:21
You don't just "remove brackets", you need to recognize what exactly they represent. Your json represents an array of objects. To think of it any other way is just downright wrong.
– Jeff Mercado
Jul 27 '15 at 1:21
add a comment |
2 Answers
2
active
oldest
votes
1
Just serialize the dictionary:
result = "MetaData": , "SRData": dResult
print(json.dumps(result, sort_keys=True, indent=4))
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
add a comment |
1
The brackets denote a JSON array, containing one element in your example. In Python, simply pick out the first element of the root array and convert back to JSON.
import json
data = json.loads('[...]')
str = json.dumps(data[0])
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Just serialize the dictionary:
result = "MetaData": , "SRData": dResult
print(json.dumps(result, sort_keys=True, indent=4))
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
add a comment |
1
Just serialize the dictionary:
result = "MetaData": , "SRData": dResult
print(json.dumps(result, sort_keys=True, indent=4))
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
add a comment |
1
1
1
Just serialize the dictionary:
result = "MetaData": , "SRData": dResult
print(json.dumps(result, sort_keys=True, indent=4))
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
Just serialize the dictionary:
result = "MetaData": , "SRData": dResult
print(json.dumps(result, sort_keys=True, indent=4))
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
answered Jul 27 '15 at 1:09
alecxealecxe
326k71641865
326k71641865
add a comment |
add a comment |
1
The brackets denote a JSON array, containing one element in your example. In Python, simply pick out the first element of the root array and convert back to JSON.
import json
data = json.loads('[...]')
str = json.dumps(data[0])
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
add a comment |
1
The brackets denote a JSON array, containing one element in your example. In Python, simply pick out the first element of the root array and convert back to JSON.
import json
data = json.loads('[...]')
str = json.dumps(data[0])
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
add a comment |
1
1
1
The brackets denote a JSON array, containing one element in your example. In Python, simply pick out the first element of the root array and convert back to JSON.
import json
data = json.loads('[...]')
str = json.dumps(data[0])
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
The brackets denote a JSON array, containing one element in your example. In Python, simply pick out the first element of the root array and convert back to JSON.
import json
data = json.loads('[...]')
str = json.dumps(data[0])
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
answered Jul 27 '15 at 1:10
VorticoVortico
1,2101433
1,2101433
add a comment |
add a comment |
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You may not really want to do the because it may force other code that deals with the result have to check whether it is a list or dictionary (or assume it's one or the other and use
try/exceptin handle the situation when the assumption is incorrect.– martineau
Jul 27 '15 at 1:21
You don't just "remove brackets", you need to recognize what exactly they represent. Your json represents an array of objects. To think of it any other way is just downright wrong.
– Jeff Mercado
Jul 27 '15 at 1:21