How to navigate to another page after executing codes in a function in react-native
When I click the Submit button, there is a function named registerNow()
should be called.In that function, I have to check a condition and based on that condition, i have to navigate to the corresponding page. The following is the button declaration.
<Button onPress=() => this.registerNow() title="Submit"/>
and using the following statement to navigate to login page.
this.navigateToScreen('Login');
When i try to call this function directly from Onpress
button click, it is working perfectly. But not working, while calling from somewhere from other functions.
Here is my dependencies list
"dependencies":
"babel-eslint": "^8.0.0",
"react": "16.6.0-alpha.8af6728",
"react-native": "0.57.4",
"react-navigation": "^1.0.0-beta.11"
Thank you
react-native
add a comment |
When I click the Submit button, there is a function named registerNow()
should be called.In that function, I have to check a condition and based on that condition, i have to navigate to the corresponding page. The following is the button declaration.
<Button onPress=() => this.registerNow() title="Submit"/>
and using the following statement to navigate to login page.
this.navigateToScreen('Login');
When i try to call this function directly from Onpress
button click, it is working perfectly. But not working, while calling from somewhere from other functions.
Here is my dependencies list
"dependencies":
"babel-eslint": "^8.0.0",
"react": "16.6.0-alpha.8af6728",
"react-native": "0.57.4",
"react-navigation": "^1.0.0-beta.11"
Thank you
react-native
Update yourreact-navigation
package to"react-navigation": "^2.9.1",
– Naveed Sheriffdeen
Nov 14 '18 at 11:25
add a comment |
When I click the Submit button, there is a function named registerNow()
should be called.In that function, I have to check a condition and based on that condition, i have to navigate to the corresponding page. The following is the button declaration.
<Button onPress=() => this.registerNow() title="Submit"/>
and using the following statement to navigate to login page.
this.navigateToScreen('Login');
When i try to call this function directly from Onpress
button click, it is working perfectly. But not working, while calling from somewhere from other functions.
Here is my dependencies list
"dependencies":
"babel-eslint": "^8.0.0",
"react": "16.6.0-alpha.8af6728",
"react-native": "0.57.4",
"react-navigation": "^1.0.0-beta.11"
Thank you
react-native
When I click the Submit button, there is a function named registerNow()
should be called.In that function, I have to check a condition and based on that condition, i have to navigate to the corresponding page. The following is the button declaration.
<Button onPress=() => this.registerNow() title="Submit"/>
and using the following statement to navigate to login page.
this.navigateToScreen('Login');
When i try to call this function directly from Onpress
button click, it is working perfectly. But not working, while calling from somewhere from other functions.
Here is my dependencies list
"dependencies":
"babel-eslint": "^8.0.0",
"react": "16.6.0-alpha.8af6728",
"react-native": "0.57.4",
"react-navigation": "^1.0.0-beta.11"
Thank you
react-native
react-native
edited Nov 14 '18 at 11:19
Naveed Sheriffdeen
453415
453415
asked Nov 14 '18 at 11:02
user3584409user3584409
12
12
Update yourreact-navigation
package to"react-navigation": "^2.9.1",
– Naveed Sheriffdeen
Nov 14 '18 at 11:25
add a comment |
Update yourreact-navigation
package to"react-navigation": "^2.9.1",
– Naveed Sheriffdeen
Nov 14 '18 at 11:25
Update your
react-navigation
package to "react-navigation": "^2.9.1",
– Naveed Sheriffdeen
Nov 14 '18 at 11:25
Update your
react-navigation
package to "react-navigation": "^2.9.1",
– Naveed Sheriffdeen
Nov 14 '18 at 11:25
add a comment |
1 Answer
1
active
oldest
votes
is registerNow function making an Api Call it will be better if your share your code if your function is making an Api call using Fetch or axios then it is simple by putting .then function after that and place your navigation code under the then()
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
is registerNow function making an Api Call it will be better if your share your code if your function is making an Api call using Fetch or axios then it is simple by putting .then function after that and place your navigation code under the then()
add a comment |
is registerNow function making an Api Call it will be better if your share your code if your function is making an Api call using Fetch or axios then it is simple by putting .then function after that and place your navigation code under the then()
add a comment |
is registerNow function making an Api Call it will be better if your share your code if your function is making an Api call using Fetch or axios then it is simple by putting .then function after that and place your navigation code under the then()
is registerNow function making an Api Call it will be better if your share your code if your function is making an Api call using Fetch or axios then it is simple by putting .then function after that and place your navigation code under the then()
answered Nov 14 '18 at 11:51
Muhammad ArslanMuhammad Arslan
13
13
add a comment |
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Update your
react-navigation
package to"react-navigation": "^2.9.1",
– Naveed Sheriffdeen
Nov 14 '18 at 11:25