how to get status code with urllib when using opener
0
I'm using the following code to use socks4 proxies with urllib:
import socks
import socket
import urllib.request, urllib.parse, urllib.error
import http.cookiejar
import http.client as httplib
proxy = task
ip, port = proxy.split(":")
socket.setdefaulttimeout(timeout_value)
log_msg = str("Trying Socks4 proxy%21s " % proxy)
socks.set_default_proxy(socks.SOCKS4, ip, int(port))
socket.socket = socks.socksocket
cj = http.cookiejar.CookieJar()
opener = urllib.request.build_opener(
urllib.request.HTTPCookieProcessor(cj),
urllib.request.HTTPRedirectHandler(),
)
try:
opener.addheaders = [('User-Agent','Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_4) AppleWebKit/603.1.30 (KHTML, like Gecko) Version/10.1 Safari/603.1.30')]
response = opener.open("https://www.google.com/search?q=iamtesting", timeout=timeout_value).read().decode("utf-8")
Now, how do I get the status code like 404 200 502 , I tried response.code() and response.getcode() but it both says they dont exist.
python python-3.x urllib
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
add a comment |
0
I'm using the following code to use socks4 proxies with urllib:
import socks
import socket
import urllib.request, urllib.parse, urllib.error
import http.cookiejar
import http.client as httplib
proxy = task
ip, port = proxy.split(":")
socket.setdefaulttimeout(timeout_value)
log_msg = str("Trying Socks4 proxy%21s " % proxy)
socks.set_default_proxy(socks.SOCKS4, ip, int(port))
socket.socket = socks.socksocket
cj = http.cookiejar.CookieJar()
opener = urllib.request.build_opener(
urllib.request.HTTPCookieProcessor(cj),
urllib.request.HTTPRedirectHandler(),
)
try:
opener.addheaders = [('User-Agent','Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_4) AppleWebKit/603.1.30 (KHTML, like Gecko) Version/10.1 Safari/603.1.30')]
response = opener.open("https://www.google.com/search?q=iamtesting", timeout=timeout_value).read().decode("utf-8")
Now, how do I get the status code like 404 200 502 , I tried response.code() and response.getcode() but it both says they dont exist.
python python-3.x urllib
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
add a comment |
0
0
0
I'm using the following code to use socks4 proxies with urllib:
import socks
import socket
import urllib.request, urllib.parse, urllib.error
import http.cookiejar
import http.client as httplib
proxy = task
ip, port = proxy.split(":")
socket.setdefaulttimeout(timeout_value)
log_msg = str("Trying Socks4 proxy%21s " % proxy)
socks.set_default_proxy(socks.SOCKS4, ip, int(port))
socket.socket = socks.socksocket
cj = http.cookiejar.CookieJar()
opener = urllib.request.build_opener(
urllib.request.HTTPCookieProcessor(cj),
urllib.request.HTTPRedirectHandler(),
)
try:
opener.addheaders = [('User-Agent','Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_4) AppleWebKit/603.1.30 (KHTML, like Gecko) Version/10.1 Safari/603.1.30')]
response = opener.open("https://www.google.com/search?q=iamtesting", timeout=timeout_value).read().decode("utf-8")
Now, how do I get the status code like 404 200 502 , I tried response.code() and response.getcode() but it both says they dont exist.
python python-3.x urllib
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
I'm using the following code to use socks4 proxies with urllib:
import socks
import socket
import urllib.request, urllib.parse, urllib.error
import http.cookiejar
import http.client as httplib
proxy = task
ip, port = proxy.split(":")
socket.setdefaulttimeout(timeout_value)
log_msg = str("Trying Socks4 proxy%21s " % proxy)
socks.set_default_proxy(socks.SOCKS4, ip, int(port))
socket.socket = socks.socksocket
cj = http.cookiejar.CookieJar()
opener = urllib.request.build_opener(
urllib.request.HTTPCookieProcessor(cj),
urllib.request.HTTPRedirectHandler(),
)
try:
opener.addheaders = [('User-Agent','Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_4) AppleWebKit/603.1.30 (KHTML, like Gecko) Version/10.1 Safari/603.1.30')]
response = opener.open("https://www.google.com/search?q=iamtesting", timeout=timeout_value).read().decode("utf-8")
Now, how do I get the status code like 404 200 502 , I tried response.code() and response.getcode() but it both says they dont exist.
python python-3.x urllib
python python-3.x urllib
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
asked Nov 14 '18 at 20:15
ThiplolThiplol
558
558
add a comment |
add a comment |
0
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