How to initialize static std::array with static const variable?










-2














How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array is relatively new so theres not much to be found.



// ExampleClass.h
class ExampleClass
public:
static const size_t NUMBER_OF_INDEXES = 5;
private:
static std::array<int, NUMBER_OF_INDEXES> myArray;
;









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    -2














    How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array is relatively new so theres not much to be found.



    // ExampleClass.h
    class ExampleClass
    public:
    static const size_t NUMBER_OF_INDEXES = 5;
    private:
    static std::array<int, NUMBER_OF_INDEXES> myArray;
    ;









    share|improve this question
























      -2












      -2








      -2







      How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array is relatively new so theres not much to be found.



      // ExampleClass.h
      class ExampleClass
      public:
      static const size_t NUMBER_OF_INDEXES = 5;
      private:
      static std::array<int, NUMBER_OF_INDEXES> myArray;
      ;









      share|improve this question













      How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array is relatively new so theres not much to be found.



      // ExampleClass.h
      class ExampleClass
      public:
      static const size_t NUMBER_OF_INDEXES = 5;
      private:
      static std::array<int, NUMBER_OF_INDEXES> myArray;
      ;






      c++ c++11 stdarray






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      asked Nov 12 '18 at 23:13









      Zax FtwZax Ftw

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      176






















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          Like any other static data member, ExampleClass::myArray should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:



          std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;





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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            Like any other static data member, ExampleClass::myArray should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:



            std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;





            share|improve this answer

























              1














              Like any other static data member, ExampleClass::myArray should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:



              std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;





              share|improve this answer























                1












                1








                1






                Like any other static data member, ExampleClass::myArray should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:



                std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;





                share|improve this answer












                Like any other static data member, ExampleClass::myArray should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:



                std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;






                share|improve this answer












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                answered Nov 12 '18 at 23:17









                BrianBrian

                63.9k794180




                63.9k794180



























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