How to initialize static std::array with static const variable?
How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array
is relatively new so theres not much to be found.
// ExampleClass.h
class ExampleClass
public:
static const size_t NUMBER_OF_INDEXES = 5;
private:
static std::array<int, NUMBER_OF_INDEXES> myArray;
;
c++ c++11 stdarray
add a comment |
How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array
is relatively new so theres not much to be found.
// ExampleClass.h
class ExampleClass
public:
static const size_t NUMBER_OF_INDEXES = 5;
private:
static std::array<int, NUMBER_OF_INDEXES> myArray;
;
c++ c++11 stdarray
add a comment |
How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array
is relatively new so theres not much to be found.
// ExampleClass.h
class ExampleClass
public:
static const size_t NUMBER_OF_INDEXES = 5;
private:
static std::array<int, NUMBER_OF_INDEXES> myArray;
;
c++ c++11 stdarray
How to initialize static std:array that uses static const variable as size? I tried searching for similar questions but std::array
is relatively new so theres not much to be found.
// ExampleClass.h
class ExampleClass
public:
static const size_t NUMBER_OF_INDEXES = 5;
private:
static std::array<int, NUMBER_OF_INDEXES> myArray;
;
c++ c++11 stdarray
c++ c++11 stdarray
asked Nov 12 '18 at 23:13
Zax FtwZax Ftw
176
176
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add a comment |
1 Answer
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Like any other static data member, ExampleClass::myArray
should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:
std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Like any other static data member, ExampleClass::myArray
should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:
std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;
add a comment |
Like any other static data member, ExampleClass::myArray
should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:
std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;
add a comment |
Like any other static data member, ExampleClass::myArray
should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:
std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;
Like any other static data member, ExampleClass::myArray
should have an out-of-line definition in exactly one translation unit, where you write down its type and its qualified name as usual:
std::array<int, ExampleClass::NUMBER_OF_INDEXES> ExampleClass::myArray = 1, 2, 3, 4, 5;
answered Nov 12 '18 at 23:17
BrianBrian
63.9k794180
63.9k794180
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