How to display an Image in a different Form with simple Button press
I have 2 Forms. The first one contains a Button and the other contains a PictureBox.
Now I want to display the PictureBox when the Button is pressed.
I have tried with this code:
private void button3_Click(object sender, EventArgs e)
// in order to hide the first form
this.Hide();
Form2 f1 = new Form2();
f1.ShowDialog();
// to display the pic the second form
Form2.pictureBox1.Visible = true;
But the problem was that it was inaccessible due to protection level.
What can I do?
c#
edited Nov 13 '18 at 8:44
Jimi
7,41241833
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
add a comment |
I have 2 Forms. The first one contains a Button and the other contains a PictureBox.
Now I want to display the PictureBox when the Button is pressed.
I have tried with this code:
private void button3_Click(object sender, EventArgs e)
// in order to hide the first form
this.Hide();
Form2 f1 = new Form2();
f1.ShowDialog();
// to display the pic the second form
Form2.pictureBox1.Visible = true;
But the problem was that it was inaccessible due to protection level.
What can I do?
c#
edited Nov 13 '18 at 8:44
Jimi
7,41241833
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
1
What do you mean with I am using VB.net (c#)? The code you're showing is C#, not VB.Net. Pick one, different languages. -- Having an instance ofForm2created asForm2 f1 = new Form2();, you will then be accessing a Control inForm2withf1.PictureBox.Visible = true;.. Before.ShowDialog();. -- An instance ofForm2named asf1can be quite confusing.
– Jimi
Nov 13 '18 at 7:11
oh sorry about that i meant c#
– AceSiddig
Nov 13 '18 at 7:36
Ok i tried that it said form 1 does not contain definition for 'pictureBox1' and no extension method for 'pictureBox1'.
– AceSiddig
Nov 13 '18 at 7:43
Apparently,pictureBox1is inForm2, notForm1. A piece of the code you have written is not correct. When something is not working, post the code you're actually using, updating you question.
– Jimi
Nov 13 '18 at 7:47
yes its in form 2 and thanks
– AceSiddig
Nov 13 '18 at 8:08
add a comment |
I have 2 Forms. The first one contains a Button and the other contains a PictureBox.
Now I want to display the PictureBox when the Button is pressed.
I have tried with this code:
private void button3_Click(object sender, EventArgs e)
// in order to hide the first form
this.Hide();
Form2 f1 = new Form2();
f1.ShowDialog();
// to display the pic the second form
Form2.pictureBox1.Visible = true;
But the problem was that it was inaccessible due to protection level.
What can I do?
c#
edited Nov 13 '18 at 8:44
Jimi
7,41241833
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
I have 2 Forms. The first one contains a Button and the other contains a PictureBox.
Now I want to display the PictureBox when the Button is pressed.
I have tried with this code:
private void button3_Click(object sender, EventArgs e)
// in order to hide the first form
this.Hide();
Form2 f1 = new Form2();
f1.ShowDialog();
// to display the pic the second form
Form2.pictureBox1.Visible = true;
But the problem was that it was inaccessible due to protection level.
What can I do?
c#
c#
edited Nov 13 '18 at 8:44
Jimi
7,41241833
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
edited Nov 13 '18 at 8:44
Jimi
7,41241833
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
edited Nov 13 '18 at 8:44
Jimi
7,41241833
edited Nov 13 '18 at 8:44
Jimi
7,41241833
edited Nov 13 '18 at 8:44
Jimi
7,41241833
7,41241833
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
asked Nov 13 '18 at 7:05
AceSiddigAceSiddig
27
27
1
What do you mean with I am using VB.net (c#)? The code you're showing is C#, not VB.Net. Pick one, different languages. -- Having an instance ofForm2created asForm2 f1 = new Form2();, you will then be accessing a Control inForm2withf1.PictureBox.Visible = true;.. Before.ShowDialog();. -- An instance ofForm2named asf1can be quite confusing.
– Jimi
Nov 13 '18 at 7:11
oh sorry about that i meant c#
– AceSiddig
Nov 13 '18 at 7:36
Ok i tried that it said form 1 does not contain definition for 'pictureBox1' and no extension method for 'pictureBox1'.
– AceSiddig
Nov 13 '18 at 7:43
Apparently,pictureBox1is inForm2, notForm1. A piece of the code you have written is not correct. When something is not working, post the code you're actually using, updating you question.
– Jimi
Nov 13 '18 at 7:47
yes its in form 2 and thanks
– AceSiddig
Nov 13 '18 at 8:08
add a comment |
1
What do you mean with I am using VB.net (c#)? The code you're showing is C#, not VB.Net. Pick one, different languages. -- Having an instance ofForm2created asForm2 f1 = new Form2();, you will then be accessing a Control inForm2withf1.PictureBox.Visible = true;.. Before.ShowDialog();. -- An instance ofForm2named asf1can be quite confusing.
– Jimi
Nov 13 '18 at 7:11
oh sorry about that i meant c#
– AceSiddig
Nov 13 '18 at 7:36
Ok i tried that it said form 1 does not contain definition for 'pictureBox1' and no extension method for 'pictureBox1'.
– AceSiddig
Nov 13 '18 at 7:43
Apparently,pictureBox1is inForm2, notForm1. A piece of the code you have written is not correct. When something is not working, post the code you're actually using, updating you question.
– Jimi
Nov 13 '18 at 7:47
yes its in form 2 and thanks
– AceSiddig
Nov 13 '18 at 8:08
1
1
What do you mean with I am using VB.net (c#)? The code you're showing is C#, not VB.Net. Pick one, different languages. -- Having an instance of
Form2 created as Form2 f1 = new Form2();, you will then be accessing a Control in Form2 with f1.PictureBox.Visible = true;.. Before .ShowDialog();. -- An instance of Form2 named as f1 can be quite confusing.– Jimi
Nov 13 '18 at 7:11
What do you mean with I am using VB.net (c#)? The code you're showing is C#, not VB.Net. Pick one, different languages. -- Having an instance of
Form2 created as Form2 f1 = new Form2();, you will then be accessing a Control in Form2 with f1.PictureBox.Visible = true;.. Before .ShowDialog();. -- An instance of Form2 named as f1 can be quite confusing.– Jimi
Nov 13 '18 at 7:11
oh sorry about that i meant c#
– AceSiddig
Nov 13 '18 at 7:36
oh sorry about that i meant c#
– AceSiddig
Nov 13 '18 at 7:36
Ok i tried that it said form 1 does not contain definition for 'pictureBox1' and no extension method for 'pictureBox1'.
– AceSiddig
Nov 13 '18 at 7:43
Ok i tried that it said form 1 does not contain definition for 'pictureBox1' and no extension method for 'pictureBox1'.
– AceSiddig
Nov 13 '18 at 7:43
Apparently,
pictureBox1 is in Form2, not Form1. A piece of the code you have written is not correct. When something is not working, post the code you're actually using, updating you question.– Jimi
Nov 13 '18 at 7:47
Apparently,
pictureBox1 is in Form2, not Form1. A piece of the code you have written is not correct. When something is not working, post the code you're actually using, updating you question.– Jimi
Nov 13 '18 at 7:47
yes its in form 2 and thanks
– AceSiddig
Nov 13 '18 at 8:08
yes its in form 2 and thanks
– AceSiddig
Nov 13 '18 at 8:08
add a comment |
1 Answer
1
active
oldest
votes
One Way is to Pass the Image Path (string) as argument to Form2. i.e. Create a constructor for Form2 taking a string param. Do the Image Assignment & Visibility thing in Form2 Constructor (obvisouly after InitializeComponents()).
Hack Fix way is to make the PictureBox in Form2 (designer) as Public.
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
One Way is to Pass the Image Path (string) as argument to Form2. i.e. Create a constructor for Form2 taking a string param. Do the Image Assignment & Visibility thing in Form2 Constructor (obvisouly after InitializeComponents()).
Hack Fix way is to make the PictureBox in Form2 (designer) as Public.
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
add a comment |
One Way is to Pass the Image Path (string) as argument to Form2. i.e. Create a constructor for Form2 taking a string param. Do the Image Assignment & Visibility thing in Form2 Constructor (obvisouly after InitializeComponents()).
Hack Fix way is to make the PictureBox in Form2 (designer) as Public.
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
add a comment |
One Way is to Pass the Image Path (string) as argument to Form2. i.e. Create a constructor for Form2 taking a string param. Do the Image Assignment & Visibility thing in Form2 Constructor (obvisouly after InitializeComponents()).
Hack Fix way is to make the PictureBox in Form2 (designer) as Public.
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
One Way is to Pass the Image Path (string) as argument to Form2. i.e. Create a constructor for Form2 taking a string param. Do the Image Assignment & Visibility thing in Form2 Constructor (obvisouly after InitializeComponents()).
Hack Fix way is to make the PictureBox in Form2 (designer) as Public.
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
answered Nov 13 '18 at 7:08
Prateek ShrivastavaPrateek Shrivastava
888511
888511
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
add a comment |
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
sorry but am still new to this how can i do that, i changed the picBox to public ok, and created the constructor but still the problem remains
– AceSiddig
Nov 13 '18 at 7:58
add a comment |
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1
What do you mean with I am using VB.net (c#)? The code you're showing is C#, not VB.Net. Pick one, different languages. -- Having an instance of
Form2created asForm2 f1 = new Form2();, you will then be accessing a Control inForm2withf1.PictureBox.Visible = true;.. Before.ShowDialog();. -- An instance ofForm2named asf1can be quite confusing.– Jimi
Nov 13 '18 at 7:11
oh sorry about that i meant c#
– AceSiddig
Nov 13 '18 at 7:36
Ok i tried that it said form 1 does not contain definition for 'pictureBox1' and no extension method for 'pictureBox1'.
– AceSiddig
Nov 13 '18 at 7:43
Apparently,
pictureBox1is inForm2, notForm1. A piece of the code you have written is not correct. When something is not working, post the code you're actually using, updating you question.– Jimi
Nov 13 '18 at 7:47
yes its in form 2 and thanks
– AceSiddig
Nov 13 '18 at 8:08