User Defined Exception is not working in JavaScript Promise










2














I implement user-defined exception in javascript code but it is not catching the exception.



I am providing my code :



function sendRequest(URL, Data, authorization, requestType,cuboidName) 
var Response = new $.Deferred();
var json;
if (requestType.toString() == "GET")
$.ajax(
url: URL,
type: "GET",
dataType: "json",
headers:
'Authorization': authorization,
'Accept': 'application/json'
,
success: function (result)
Response.resolve(result);
//console.log("Response : " + JSON.stringify(result) + "nnn");

,
error: function(err)
throw new Error("Error Code:t"+err.status+"nReason:tCuboid Download failed for Cuboid:"+cuboidName);

);

return Response.promise();



I am calling the sendRequest function from the following code :



async loadDatatypeCuboid(dataCuboid)

try

dataTypeCuboiId = "444";
var res3 = new $.Deferred();
Utils.sendRequest(this.baseUrl+"rest/v1/grid/"+dataTypeCuboiId+"?importTid=-1&view=LATEST&mode=0&baselineId=-1", null, Globals.authorization, "GET","Datatype").then(function (result)
res3.resolve(result);
if (result.status == 500)
return;

else


);
return res3.promise();

catch (error)

console.log(error);




I am not able to catch the thrown error. The console is showing as :




Utils.js:26 Uncaught Error: Error Code: 500 Reason: Cuboid Download
failed for Cuboid:Datatype




can anyone suggest How to Handle Exceptions in JavaScript Promise?
Thanks in Advance










share|improve this question























  • Possible duplicate of How do I handle errors with promises? - the issue is that you are not using the .catch method on the returned promise. try-catch won't work because Promises hide the exception under the .catch call. If you don't have one then the error will be "silenced" and never thrown outside the Promise.
    – Sergiu Paraschiv
    Nov 12 at 11:02
















2














I implement user-defined exception in javascript code but it is not catching the exception.



I am providing my code :



function sendRequest(URL, Data, authorization, requestType,cuboidName) 
var Response = new $.Deferred();
var json;
if (requestType.toString() == "GET")
$.ajax(
url: URL,
type: "GET",
dataType: "json",
headers:
'Authorization': authorization,
'Accept': 'application/json'
,
success: function (result)
Response.resolve(result);
//console.log("Response : " + JSON.stringify(result) + "nnn");

,
error: function(err)
throw new Error("Error Code:t"+err.status+"nReason:tCuboid Download failed for Cuboid:"+cuboidName);

);

return Response.promise();



I am calling the sendRequest function from the following code :



async loadDatatypeCuboid(dataCuboid)

try

dataTypeCuboiId = "444";
var res3 = new $.Deferred();
Utils.sendRequest(this.baseUrl+"rest/v1/grid/"+dataTypeCuboiId+"?importTid=-1&view=LATEST&mode=0&baselineId=-1", null, Globals.authorization, "GET","Datatype").then(function (result)
res3.resolve(result);
if (result.status == 500)
return;

else


);
return res3.promise();

catch (error)

console.log(error);




I am not able to catch the thrown error. The console is showing as :




Utils.js:26 Uncaught Error: Error Code: 500 Reason: Cuboid Download
failed for Cuboid:Datatype




can anyone suggest How to Handle Exceptions in JavaScript Promise?
Thanks in Advance










share|improve this question























  • Possible duplicate of How do I handle errors with promises? - the issue is that you are not using the .catch method on the returned promise. try-catch won't work because Promises hide the exception under the .catch call. If you don't have one then the error will be "silenced" and never thrown outside the Promise.
    – Sergiu Paraschiv
    Nov 12 at 11:02














2












2








2







I implement user-defined exception in javascript code but it is not catching the exception.



I am providing my code :



function sendRequest(URL, Data, authorization, requestType,cuboidName) 
var Response = new $.Deferred();
var json;
if (requestType.toString() == "GET")
$.ajax(
url: URL,
type: "GET",
dataType: "json",
headers:
'Authorization': authorization,
'Accept': 'application/json'
,
success: function (result)
Response.resolve(result);
//console.log("Response : " + JSON.stringify(result) + "nnn");

,
error: function(err)
throw new Error("Error Code:t"+err.status+"nReason:tCuboid Download failed for Cuboid:"+cuboidName);

);

return Response.promise();



I am calling the sendRequest function from the following code :



async loadDatatypeCuboid(dataCuboid)

try

dataTypeCuboiId = "444";
var res3 = new $.Deferred();
Utils.sendRequest(this.baseUrl+"rest/v1/grid/"+dataTypeCuboiId+"?importTid=-1&view=LATEST&mode=0&baselineId=-1", null, Globals.authorization, "GET","Datatype").then(function (result)
res3.resolve(result);
if (result.status == 500)
return;

else


);
return res3.promise();

catch (error)

console.log(error);




I am not able to catch the thrown error. The console is showing as :




Utils.js:26 Uncaught Error: Error Code: 500 Reason: Cuboid Download
failed for Cuboid:Datatype




can anyone suggest How to Handle Exceptions in JavaScript Promise?
Thanks in Advance










share|improve this question















I implement user-defined exception in javascript code but it is not catching the exception.



I am providing my code :



function sendRequest(URL, Data, authorization, requestType,cuboidName) 
var Response = new $.Deferred();
var json;
if (requestType.toString() == "GET")
$.ajax(
url: URL,
type: "GET",
dataType: "json",
headers:
'Authorization': authorization,
'Accept': 'application/json'
,
success: function (result)
Response.resolve(result);
//console.log("Response : " + JSON.stringify(result) + "nnn");

,
error: function(err)
throw new Error("Error Code:t"+err.status+"nReason:tCuboid Download failed for Cuboid:"+cuboidName);

);

return Response.promise();



I am calling the sendRequest function from the following code :



async loadDatatypeCuboid(dataCuboid)

try

dataTypeCuboiId = "444";
var res3 = new $.Deferred();
Utils.sendRequest(this.baseUrl+"rest/v1/grid/"+dataTypeCuboiId+"?importTid=-1&view=LATEST&mode=0&baselineId=-1", null, Globals.authorization, "GET","Datatype").then(function (result)
res3.resolve(result);
if (result.status == 500)
return;

else


);
return res3.promise();

catch (error)

console.log(error);




I am not able to catch the thrown error. The console is showing as :




Utils.js:26 Uncaught Error: Error Code: 500 Reason: Cuboid Download
failed for Cuboid:Datatype




can anyone suggest How to Handle Exceptions in JavaScript Promise?
Thanks in Advance







javascript asynchronous exception-handling es6-promise throw






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 11:17









Yashwardhan Pauranik

1,79311226




1,79311226










asked Nov 12 at 10:57









Jaydeep Bobade

276110




276110











  • Possible duplicate of How do I handle errors with promises? - the issue is that you are not using the .catch method on the returned promise. try-catch won't work because Promises hide the exception under the .catch call. If you don't have one then the error will be "silenced" and never thrown outside the Promise.
    – Sergiu Paraschiv
    Nov 12 at 11:02

















  • Possible duplicate of How do I handle errors with promises? - the issue is that you are not using the .catch method on the returned promise. try-catch won't work because Promises hide the exception under the .catch call. If you don't have one then the error will be "silenced" and never thrown outside the Promise.
    – Sergiu Paraschiv
    Nov 12 at 11:02
















Possible duplicate of How do I handle errors with promises? - the issue is that you are not using the .catch method on the returned promise. try-catch won't work because Promises hide the exception under the .catch call. If you don't have one then the error will be "silenced" and never thrown outside the Promise.
– Sergiu Paraschiv
Nov 12 at 11:02





Possible duplicate of How do I handle errors with promises? - the issue is that you are not using the .catch method on the returned promise. try-catch won't work because Promises hide the exception under the .catch call. If you don't have one then the error will be "silenced" and never thrown outside the Promise.
– Sergiu Paraschiv
Nov 12 at 11:02


















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