Subtract n from every element of a Clojure sequence










1














I assume this is a very simple question, but I can't seem to find the answer online: how do you subtract n from every element of a Clojure sequence? E.g subtract 4 from each element of (6 9 11) and get (2 5 7)?



I assume this should be done with map, and I know that for the special case of subtracting 1 I can do (map dec (sequence)), but how do I do it for any other case?



For what it's worth, I figured out eventually that (map - (map (partial - n) (sequence)) technically does work, but it's clearly not how this is meant to be done.




For anyone who lands here from search and has a slightly different problem: if you want to subtract every element of a Clojure sequence from n, you can do that with (map (partial - n) (sequence))



Similarly, for multiplying every element of a Clojure sequence by n you can do (map (partial * n) (sequence))



For adding n to every element of a Clojure sequence (map (partial + n) (sequence))



I found that answer in these Clojure docs so I assume it's idiomatic, but obviously I'm not able to vouch for that myself.










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    1














    I assume this is a very simple question, but I can't seem to find the answer online: how do you subtract n from every element of a Clojure sequence? E.g subtract 4 from each element of (6 9 11) and get (2 5 7)?



    I assume this should be done with map, and I know that for the special case of subtracting 1 I can do (map dec (sequence)), but how do I do it for any other case?



    For what it's worth, I figured out eventually that (map - (map (partial - n) (sequence)) technically does work, but it's clearly not how this is meant to be done.




    For anyone who lands here from search and has a slightly different problem: if you want to subtract every element of a Clojure sequence from n, you can do that with (map (partial - n) (sequence))



    Similarly, for multiplying every element of a Clojure sequence by n you can do (map (partial * n) (sequence))



    For adding n to every element of a Clojure sequence (map (partial + n) (sequence))



    I found that answer in these Clojure docs so I assume it's idiomatic, but obviously I'm not able to vouch for that myself.










    share|improve this question
























      1












      1








      1







      I assume this is a very simple question, but I can't seem to find the answer online: how do you subtract n from every element of a Clojure sequence? E.g subtract 4 from each element of (6 9 11) and get (2 5 7)?



      I assume this should be done with map, and I know that for the special case of subtracting 1 I can do (map dec (sequence)), but how do I do it for any other case?



      For what it's worth, I figured out eventually that (map - (map (partial - n) (sequence)) technically does work, but it's clearly not how this is meant to be done.




      For anyone who lands here from search and has a slightly different problem: if you want to subtract every element of a Clojure sequence from n, you can do that with (map (partial - n) (sequence))



      Similarly, for multiplying every element of a Clojure sequence by n you can do (map (partial * n) (sequence))



      For adding n to every element of a Clojure sequence (map (partial + n) (sequence))



      I found that answer in these Clojure docs so I assume it's idiomatic, but obviously I'm not able to vouch for that myself.










      share|improve this question













      I assume this is a very simple question, but I can't seem to find the answer online: how do you subtract n from every element of a Clojure sequence? E.g subtract 4 from each element of (6 9 11) and get (2 5 7)?



      I assume this should be done with map, and I know that for the special case of subtracting 1 I can do (map dec (sequence)), but how do I do it for any other case?



      For what it's worth, I figured out eventually that (map - (map (partial - n) (sequence)) technically does work, but it's clearly not how this is meant to be done.




      For anyone who lands here from search and has a slightly different problem: if you want to subtract every element of a Clojure sequence from n, you can do that with (map (partial - n) (sequence))



      Similarly, for multiplying every element of a Clojure sequence by n you can do (map (partial * n) (sequence))



      For adding n to every element of a Clojure sequence (map (partial + n) (sequence))



      I found that answer in these Clojure docs so I assume it's idiomatic, but obviously I'm not able to vouch for that myself.







      clojure






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      share|improve this question











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      asked Nov 12 at 8:51









      marbiru

      204




      204






















          3 Answers
          3






          active

          oldest

          votes


















          2














          An anonymous function literal is convenient here:



          > (map #(- % 4) [6 9 11])
          (2 5 7)


          The #(- % 4) form is short-hand for the anonymous function in



          > (map (fn [x] (- x 4)) [6 9 11])
          (2 5 7)





          share|improve this answer




























            0














            If you're looking for a combinatory expression for the function you want, try (comp - (partial - 4)):



            => (map (comp - (partial - 4)) '(6 9 11))
            (2 5 7)


            Remember that + and - are just ordinary named Clojure functions. The function that you need is probably not worth naming, so you express it directly as #(- % 4) or (fn [n] (- n 4)), or as above.



            It is also worth remembering that map is lazy, so can deal with endless sequences:



            => (take 10 (map (comp - (partial - 4)) (range)))
            (-4 -3 -2 -1 0 1 2 3 4 5)





            share|improve this answer




























              -1














              This can be achieved through maps. Clojure maps takes a function and list as an argument.
              Synatax:




              (map (function) (seq))




              test=> (map (fn[arg] (- arg 4) ) '(7 8 9) )
              (3 4 5)
              test=> (map (fn[arg] (- arg 4) ) [7 8 9] )
              (3 4 5)


              Map can take function in shorthand notation too.




              (- % 4)




              . Here % is argument passed. Defaults to first argument. %1 to explicitly say first argument



              test=> (map #(- %1 4) [7 8 9])
              (3 4 5)
              test=> (map #(- % 4) [7 8 9])
              (3 4 5)





              share|improve this answer




















              • Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                – Shlomi
                Nov 13 at 4:23











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              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              An anonymous function literal is convenient here:



              > (map #(- % 4) [6 9 11])
              (2 5 7)


              The #(- % 4) form is short-hand for the anonymous function in



              > (map (fn [x] (- x 4)) [6 9 11])
              (2 5 7)





              share|improve this answer

























                2














                An anonymous function literal is convenient here:



                > (map #(- % 4) [6 9 11])
                (2 5 7)


                The #(- % 4) form is short-hand for the anonymous function in



                > (map (fn [x] (- x 4)) [6 9 11])
                (2 5 7)





                share|improve this answer























                  2












                  2








                  2






                  An anonymous function literal is convenient here:



                  > (map #(- % 4) [6 9 11])
                  (2 5 7)


                  The #(- % 4) form is short-hand for the anonymous function in



                  > (map (fn [x] (- x 4)) [6 9 11])
                  (2 5 7)





                  share|improve this answer












                  An anonymous function literal is convenient here:



                  > (map #(- % 4) [6 9 11])
                  (2 5 7)


                  The #(- % 4) form is short-hand for the anonymous function in



                  > (map (fn [x] (- x 4)) [6 9 11])
                  (2 5 7)






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 12 at 9:37









                  jas

                  7,11621632




                  7,11621632























                      0














                      If you're looking for a combinatory expression for the function you want, try (comp - (partial - 4)):



                      => (map (comp - (partial - 4)) '(6 9 11))
                      (2 5 7)


                      Remember that + and - are just ordinary named Clojure functions. The function that you need is probably not worth naming, so you express it directly as #(- % 4) or (fn [n] (- n 4)), or as above.



                      It is also worth remembering that map is lazy, so can deal with endless sequences:



                      => (take 10 (map (comp - (partial - 4)) (range)))
                      (-4 -3 -2 -1 0 1 2 3 4 5)





                      share|improve this answer

























                        0














                        If you're looking for a combinatory expression for the function you want, try (comp - (partial - 4)):



                        => (map (comp - (partial - 4)) '(6 9 11))
                        (2 5 7)


                        Remember that + and - are just ordinary named Clojure functions. The function that you need is probably not worth naming, so you express it directly as #(- % 4) or (fn [n] (- n 4)), or as above.



                        It is also worth remembering that map is lazy, so can deal with endless sequences:



                        => (take 10 (map (comp - (partial - 4)) (range)))
                        (-4 -3 -2 -1 0 1 2 3 4 5)





                        share|improve this answer























                          0












                          0








                          0






                          If you're looking for a combinatory expression for the function you want, try (comp - (partial - 4)):



                          => (map (comp - (partial - 4)) '(6 9 11))
                          (2 5 7)


                          Remember that + and - are just ordinary named Clojure functions. The function that you need is probably not worth naming, so you express it directly as #(- % 4) or (fn [n] (- n 4)), or as above.



                          It is also worth remembering that map is lazy, so can deal with endless sequences:



                          => (take 10 (map (comp - (partial - 4)) (range)))
                          (-4 -3 -2 -1 0 1 2 3 4 5)





                          share|improve this answer












                          If you're looking for a combinatory expression for the function you want, try (comp - (partial - 4)):



                          => (map (comp - (partial - 4)) '(6 9 11))
                          (2 5 7)


                          Remember that + and - are just ordinary named Clojure functions. The function that you need is probably not worth naming, so you express it directly as #(- % 4) or (fn [n] (- n 4)), or as above.



                          It is also worth remembering that map is lazy, so can deal with endless sequences:



                          => (take 10 (map (comp - (partial - 4)) (range)))
                          (-4 -3 -2 -1 0 1 2 3 4 5)






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 12 at 16:09









                          Thumbnail

                          10.9k11628




                          10.9k11628





















                              -1














                              This can be achieved through maps. Clojure maps takes a function and list as an argument.
                              Synatax:




                              (map (function) (seq))




                              test=> (map (fn[arg] (- arg 4) ) '(7 8 9) )
                              (3 4 5)
                              test=> (map (fn[arg] (- arg 4) ) [7 8 9] )
                              (3 4 5)


                              Map can take function in shorthand notation too.




                              (- % 4)




                              . Here % is argument passed. Defaults to first argument. %1 to explicitly say first argument



                              test=> (map #(- %1 4) [7 8 9])
                              (3 4 5)
                              test=> (map #(- % 4) [7 8 9])
                              (3 4 5)





                              share|improve this answer




















                              • Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                                – Shlomi
                                Nov 13 at 4:23
















                              -1














                              This can be achieved through maps. Clojure maps takes a function and list as an argument.
                              Synatax:




                              (map (function) (seq))




                              test=> (map (fn[arg] (- arg 4) ) '(7 8 9) )
                              (3 4 5)
                              test=> (map (fn[arg] (- arg 4) ) [7 8 9] )
                              (3 4 5)


                              Map can take function in shorthand notation too.




                              (- % 4)




                              . Here % is argument passed. Defaults to first argument. %1 to explicitly say first argument



                              test=> (map #(- %1 4) [7 8 9])
                              (3 4 5)
                              test=> (map #(- % 4) [7 8 9])
                              (3 4 5)





                              share|improve this answer




















                              • Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                                – Shlomi
                                Nov 13 at 4:23














                              -1












                              -1








                              -1






                              This can be achieved through maps. Clojure maps takes a function and list as an argument.
                              Synatax:




                              (map (function) (seq))




                              test=> (map (fn[arg] (- arg 4) ) '(7 8 9) )
                              (3 4 5)
                              test=> (map (fn[arg] (- arg 4) ) [7 8 9] )
                              (3 4 5)


                              Map can take function in shorthand notation too.




                              (- % 4)




                              . Here % is argument passed. Defaults to first argument. %1 to explicitly say first argument



                              test=> (map #(- %1 4) [7 8 9])
                              (3 4 5)
                              test=> (map #(- % 4) [7 8 9])
                              (3 4 5)





                              share|improve this answer












                              This can be achieved through maps. Clojure maps takes a function and list as an argument.
                              Synatax:




                              (map (function) (seq))




                              test=> (map (fn[arg] (- arg 4) ) '(7 8 9) )
                              (3 4 5)
                              test=> (map (fn[arg] (- arg 4) ) [7 8 9] )
                              (3 4 5)


                              Map can take function in shorthand notation too.




                              (- % 4)




                              . Here % is argument passed. Defaults to first argument. %1 to explicitly say first argument



                              test=> (map #(- %1 4) [7 8 9])
                              (3 4 5)
                              test=> (map #(- % 4) [7 8 9])
                              (3 4 5)






                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered Nov 12 at 11:42









                              Jaiganesh

                              92




                              92











                              • Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                                – Shlomi
                                Nov 13 at 4:23

















                              • Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                                – Shlomi
                                Nov 13 at 4:23
















                              Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                              – Shlomi
                              Nov 13 at 4:23





                              Maps, the data structures, have nothing to do with map the function. Map the function applies a function f on every element in a sequence. A map data structure is storing values at keys.
                              – Shlomi
                              Nov 13 at 4:23


















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