Linux Shell Scripting recursive exponentation
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2
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I am writing a script that takes 2 numbers as an input and uses recursion to power on number to the power of the other, simple exponentiation. However I am new to scripting and cannot figure out where my syntax is errored here.
Here is the script
#!/bin/bash
echo "Enter number: "
read number
echo "Enter power: "
read power
echo "Powering $number to power of $power!"
exp ()
if [ $2 = 1 ]
then
return $1
fi
return $1 * $(exp $1 $2-1 )
result=$(exp $number, $power)
echo "Result: $result"
Currently, it kind of freezes, im not sure if I use the parameters correctly (in terms of syntax).
linux bash shell recursion command-line
add a comment |
up vote
2
down vote
favorite
I am writing a script that takes 2 numbers as an input and uses recursion to power on number to the power of the other, simple exponentiation. However I am new to scripting and cannot figure out where my syntax is errored here.
Here is the script
#!/bin/bash
echo "Enter number: "
read number
echo "Enter power: "
read power
echo "Powering $number to power of $power!"
exp ()
if [ $2 = 1 ]
then
return $1
fi
return $1 * $(exp $1 $2-1 )
result=$(exp $number, $power)
echo "Result: $result"
Currently, it kind of freezes, im not sure if I use the parameters correctly (in terms of syntax).
linux bash shell recursion command-line
This might help: How to debug a bash script?
– Cyrus
Nov 11 at 11:01
This might help:return
can only return values from 0 to 255.
– Cyrus
Nov 11 at 11:03
@Cyrus That's what I got in bash. In dash, I was able to get 2^30 (but no higher powers of two. Bad idea to use return values in any case.
– PSkocik
Nov 11 at 11:23
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I am writing a script that takes 2 numbers as an input and uses recursion to power on number to the power of the other, simple exponentiation. However I am new to scripting and cannot figure out where my syntax is errored here.
Here is the script
#!/bin/bash
echo "Enter number: "
read number
echo "Enter power: "
read power
echo "Powering $number to power of $power!"
exp ()
if [ $2 = 1 ]
then
return $1
fi
return $1 * $(exp $1 $2-1 )
result=$(exp $number, $power)
echo "Result: $result"
Currently, it kind of freezes, im not sure if I use the parameters correctly (in terms of syntax).
linux bash shell recursion command-line
I am writing a script that takes 2 numbers as an input and uses recursion to power on number to the power of the other, simple exponentiation. However I am new to scripting and cannot figure out where my syntax is errored here.
Here is the script
#!/bin/bash
echo "Enter number: "
read number
echo "Enter power: "
read power
echo "Powering $number to power of $power!"
exp ()
if [ $2 = 1 ]
then
return $1
fi
return $1 * $(exp $1 $2-1 )
result=$(exp $number, $power)
echo "Result: $result"
Currently, it kind of freezes, im not sure if I use the parameters correctly (in terms of syntax).
linux bash shell recursion command-line
linux bash shell recursion command-line
asked Nov 11 at 10:55
student126
135
135
This might help: How to debug a bash script?
– Cyrus
Nov 11 at 11:01
This might help:return
can only return values from 0 to 255.
– Cyrus
Nov 11 at 11:03
@Cyrus That's what I got in bash. In dash, I was able to get 2^30 (but no higher powers of two. Bad idea to use return values in any case.
– PSkocik
Nov 11 at 11:23
add a comment |
This might help: How to debug a bash script?
– Cyrus
Nov 11 at 11:01
This might help:return
can only return values from 0 to 255.
– Cyrus
Nov 11 at 11:03
@Cyrus That's what I got in bash. In dash, I was able to get 2^30 (but no higher powers of two. Bad idea to use return values in any case.
– PSkocik
Nov 11 at 11:23
This might help: How to debug a bash script?
– Cyrus
Nov 11 at 11:01
This might help: How to debug a bash script?
– Cyrus
Nov 11 at 11:01
This might help:
return
can only return values from 0 to 255.– Cyrus
Nov 11 at 11:03
This might help:
return
can only return values from 0 to 255.– Cyrus
Nov 11 at 11:03
@Cyrus That's what I got in bash. In dash, I was able to get 2^30 (but no higher powers of two. Bad idea to use return values in any case.
– PSkocik
Nov 11 at 11:23
@Cyrus That's what I got in bash. In dash, I was able to get 2^30 (but no higher powers of two. Bad idea to use return values in any case.
– PSkocik
Nov 11 at 11:23
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
You need $(( ))
to force arithmetic evaluation. Then you can do it with return values:
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then return $1; fi
exp $1 $(($2-1))
return $(($1 * $?))
exp $number $power; result=$?
echo "Result: $result"
but it's a bad idea, because shells kind of reserve nonzero return values to communicate failure (e.g. the above solution
will "break" set -e
).
More idiomatically, you can use stdout:
set -e
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then echo $1; return; fi
echo $(($1 * $(exp $1 $(($2-1)) ) ))
result=$(exp $number $power)
echo "Result: $result"
but that's kind of inefficient with all the subshells.
Best to avoid the recursion and simply loop:
number=2 power=7
exp ()
local res=1 i=0;
while [ $i -lt $2 ]; do res=$((res*$1)); i=$((i+1)); done
echo $res
exp $number $power
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You need $(( ))
to force arithmetic evaluation. Then you can do it with return values:
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then return $1; fi
exp $1 $(($2-1))
return $(($1 * $?))
exp $number $power; result=$?
echo "Result: $result"
but it's a bad idea, because shells kind of reserve nonzero return values to communicate failure (e.g. the above solution
will "break" set -e
).
More idiomatically, you can use stdout:
set -e
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then echo $1; return; fi
echo $(($1 * $(exp $1 $(($2-1)) ) ))
result=$(exp $number $power)
echo "Result: $result"
but that's kind of inefficient with all the subshells.
Best to avoid the recursion and simply loop:
number=2 power=7
exp ()
local res=1 i=0;
while [ $i -lt $2 ]; do res=$((res*$1)); i=$((i+1)); done
echo $res
exp $number $power
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
add a comment |
up vote
1
down vote
accepted
You need $(( ))
to force arithmetic evaluation. Then you can do it with return values:
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then return $1; fi
exp $1 $(($2-1))
return $(($1 * $?))
exp $number $power; result=$?
echo "Result: $result"
but it's a bad idea, because shells kind of reserve nonzero return values to communicate failure (e.g. the above solution
will "break" set -e
).
More idiomatically, you can use stdout:
set -e
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then echo $1; return; fi
echo $(($1 * $(exp $1 $(($2-1)) ) ))
result=$(exp $number $power)
echo "Result: $result"
but that's kind of inefficient with all the subshells.
Best to avoid the recursion and simply loop:
number=2 power=7
exp ()
local res=1 i=0;
while [ $i -lt $2 ]; do res=$((res*$1)); i=$((i+1)); done
echo $res
exp $number $power
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You need $(( ))
to force arithmetic evaluation. Then you can do it with return values:
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then return $1; fi
exp $1 $(($2-1))
return $(($1 * $?))
exp $number $power; result=$?
echo "Result: $result"
but it's a bad idea, because shells kind of reserve nonzero return values to communicate failure (e.g. the above solution
will "break" set -e
).
More idiomatically, you can use stdout:
set -e
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then echo $1; return; fi
echo $(($1 * $(exp $1 $(($2-1)) ) ))
result=$(exp $number $power)
echo "Result: $result"
but that's kind of inefficient with all the subshells.
Best to avoid the recursion and simply loop:
number=2 power=7
exp ()
local res=1 i=0;
while [ $i -lt $2 ]; do res=$((res*$1)); i=$((i+1)); done
echo $res
exp $number $power
You need $(( ))
to force arithmetic evaluation. Then you can do it with return values:
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then return $1; fi
exp $1 $(($2-1))
return $(($1 * $?))
exp $number $power; result=$?
echo "Result: $result"
but it's a bad idea, because shells kind of reserve nonzero return values to communicate failure (e.g. the above solution
will "break" set -e
).
More idiomatically, you can use stdout:
set -e
number=2 power=7
exp ()
if [ $2 -eq 1 ]; then echo $1; return; fi
echo $(($1 * $(exp $1 $(($2-1)) ) ))
result=$(exp $number $power)
echo "Result: $result"
but that's kind of inefficient with all the subshells.
Best to avoid the recursion and simply loop:
number=2 power=7
exp ()
local res=1 i=0;
while [ $i -lt $2 ]; do res=$((res*$1)); i=$((i+1)); done
echo $res
exp $number $power
edited Nov 12 at 19:06
answered Nov 11 at 11:20
PSkocik
31.7k54569
31.7k54569
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
add a comment |
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
@student126: Please take a look at: [What should I do when someone answers my question?](stackoverflow.com/help/someone-answers
– Cyrus
Nov 11 at 11:48
add a comment |
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This might help: How to debug a bash script?
– Cyrus
Nov 11 at 11:01
This might help:
return
can only return values from 0 to 255.– Cyrus
Nov 11 at 11:03
@Cyrus That's what I got in bash. In dash, I was able to get 2^30 (but no higher powers of two. Bad idea to use return values in any case.
– PSkocik
Nov 11 at 11:23