How to plot LTP vs. time from data available in a matrix in the form of Date, time, LTP
0
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
asked Nov 12 at 4:16
krishna
31
add a comment |
0
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
asked Nov 12 at 4:16
krishna
31
add a comment |
0
0
0
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
asked Nov 12 at 4:16
krishna
31
I have data in 3 columns:(as shown below
- Date Time LTP
- 20180102 09:16 1800
- ... ... ...
I wanna plot it in R so that I get time on the x-axis and LTP on the y-axis. Since there are around 360 rows every day (every minute LTP changes), the x variable shall be date:time
I am new to R and I need help in this. Thanks in anticipation
r gplots
r gplots
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
asked Nov 12 at 4:16
krishna
31
31
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53255898%2fhow-to-plot-ltp-vs-time-from-data-available-in-a-matrix-in-the-form-of-date-ti%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
0
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
0
0
0
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
Try this:
library(zoo)
z <- read.zoo("myfile.dat", header = TRUE, index = 1:2, format = "%Y%m%d %H:%M", tz = "")
# classic graphics
plot(z)
# ggplot2 graphics
autoplot(z)
Note
To generate a file for the sample data provided in the question try this; however, with only one point you won't see anything on a line graph.
cat("Date Time LTPn20180102 09:16 1800", file = "myfile.dat")
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
answered Nov 12 at 4:27
G. Grothendieck
145k9126231
145k9126231
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
add a comment |
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to useplot(z, xaxt = "n")will omit X axis. Now useaxis.breakin the plotrix package.
– G. Grothendieck
Nov 12 at 12:29
And a third approach isplot(z, xaxt = "n", type = "n"). Now uselinestwice to overlay on that empty chart each subset separately.
– G. Grothendieck
Nov 12 at 12:47
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
Thank you so much for your reply .. Yes it did help me ..however, since my data is stock data, i have no data points from (example) 20180101 15:30 to 20180102 09:08 .. and same every day ..so in such case it is simple interpolating between the two points. Is there a way to make the program understand that there are no data points there and it shall treat 20180102 09:08 as the next point on x-axis after 20180101 15:30 .. I am trying to figure out from google, but any help here would be greatly appreciated. thank you again.
– krishna
Nov 12 at 7:11
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to use
plot(z, xaxt = "n") will omit X axis. Now use axis.break in the plotrix package.– G. Grothendieck
Nov 12 at 12:29
If you insert an NA between the valid points that will cause the line to be disconnected. Another approach to indicate this is to use
plot(z, xaxt = "n") will omit X axis. Now use axis.break in the plotrix package.– G. Grothendieck
Nov 12 at 12:29
And a third approach is
plot(z, xaxt = "n", type = "n") . Now use lines twice to overlay on that empty chart each subset separately.– G. Grothendieck
Nov 12 at 12:47
And a third approach is
plot(z, xaxt = "n", type = "n") . Now use lines twice to overlay on that empty chart each subset separately.– G. Grothendieck
Nov 12 at 12:47
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53255898%2fhow-to-plot-ltp-vs-time-from-data-available-in-a-matrix-in-the-form-of-date-ti%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
