Odtnhj

Welcome I want to check if number is even , non even or not integer and I don't know how to check last case. My code:

disp('check number');
x = input('give number = ');
if mod(x,2)== 0
 disp(' even number');
elseif mod(x,2)~= 0
 disp(' not even number');
else mod(x,2)== float
 disp('non integer'); 
end

The else clause doesn't take a conditional expression, so in order to use it we need to make sure that all integers are handled before we get there. Fortunately, if we catch all even integers and all odd integers, anything left is not an integer.

The if clause looks good, if mod(x,2) == 0, then it's even, so let's keep that. For the elseif part, for all integers, mod(x,1) == 1. Normally this would catch both odd and even integers, but since we've already handled all of the even integers in the if clause, we can safely assume that any integers that get here are odd. Anything that makes it past these two conditions must be a non-integer.

disp('check number');
x = input('give number = ');
if mod(x,2) == 0
 disp(' even number');
elseif mod(x,1) == 0
 disp(' not even number');
else
 disp('non integer');
end