How to initialize point cloud from Eigen MatrixXf in c++










0















So I have an input:



double* in;


I want to make:



 pcl::PointCloud<pcl::PointXYZ>::Ptr cloud;


with the array I have.



The way I figure out is first:



Eigen::Map<Eigen::Matrix<double,Eigen::Dynamic,Eigen::Dynamic,Eigen::ColMajor> > M(in,len,chl);
Eigen::MatrixXf Mf = M.cast <float> ();


However, I am stuck here. I do not know how to initialize the point cloud with Eigen matrix.



I am thinking if



pcl::PointCloud<Eigen::MatrixXf>::Ptr cloud_ar_p(pcl::PointCloud<Eigen::MatrixXf> (Mf));


as a first step that would possible work.



Any hint and comments are so much appreciated. I am stuck for a while actually.



Thanks.










share|improve this question

















  • 1





    stackoverflow.com/questions/17129018/…

    – R zu
    Nov 15 '18 at 18:09











  • @RzuThank you so much. That answer is good!

    – Wei
    Nov 16 '18 at 0:35















0















So I have an input:



double* in;


I want to make:



 pcl::PointCloud<pcl::PointXYZ>::Ptr cloud;


with the array I have.



The way I figure out is first:



Eigen::Map<Eigen::Matrix<double,Eigen::Dynamic,Eigen::Dynamic,Eigen::ColMajor> > M(in,len,chl);
Eigen::MatrixXf Mf = M.cast <float> ();


However, I am stuck here. I do not know how to initialize the point cloud with Eigen matrix.



I am thinking if



pcl::PointCloud<Eigen::MatrixXf>::Ptr cloud_ar_p(pcl::PointCloud<Eigen::MatrixXf> (Mf));


as a first step that would possible work.



Any hint and comments are so much appreciated. I am stuck for a while actually.



Thanks.










share|improve this question

















  • 1





    stackoverflow.com/questions/17129018/…

    – R zu
    Nov 15 '18 at 18:09











  • @RzuThank you so much. That answer is good!

    – Wei
    Nov 16 '18 at 0:35













0












0








0








So I have an input:



double* in;


I want to make:



 pcl::PointCloud<pcl::PointXYZ>::Ptr cloud;


with the array I have.



The way I figure out is first:



Eigen::Map<Eigen::Matrix<double,Eigen::Dynamic,Eigen::Dynamic,Eigen::ColMajor> > M(in,len,chl);
Eigen::MatrixXf Mf = M.cast <float> ();


However, I am stuck here. I do not know how to initialize the point cloud with Eigen matrix.



I am thinking if



pcl::PointCloud<Eigen::MatrixXf>::Ptr cloud_ar_p(pcl::PointCloud<Eigen::MatrixXf> (Mf));


as a first step that would possible work.



Any hint and comments are so much appreciated. I am stuck for a while actually.



Thanks.










share|improve this question














So I have an input:



double* in;


I want to make:



 pcl::PointCloud<pcl::PointXYZ>::Ptr cloud;


with the array I have.



The way I figure out is first:



Eigen::Map<Eigen::Matrix<double,Eigen::Dynamic,Eigen::Dynamic,Eigen::ColMajor> > M(in,len,chl);
Eigen::MatrixXf Mf = M.cast <float> ();


However, I am stuck here. I do not know how to initialize the point cloud with Eigen matrix.



I am thinking if



pcl::PointCloud<Eigen::MatrixXf>::Ptr cloud_ar_p(pcl::PointCloud<Eigen::MatrixXf> (Mf));


as a first step that would possible work.



Any hint and comments are so much appreciated. I am stuck for a while actually.



Thanks.







c++ templates eigen point-cloud-library






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 1:27









WeiWei

6019




6019







  • 1





    stackoverflow.com/questions/17129018/…

    – R zu
    Nov 15 '18 at 18:09











  • @RzuThank you so much. That answer is good!

    – Wei
    Nov 16 '18 at 0:35












  • 1





    stackoverflow.com/questions/17129018/…

    – R zu
    Nov 15 '18 at 18:09











  • @RzuThank you so much. That answer is good!

    – Wei
    Nov 16 '18 at 0:35







1




1





stackoverflow.com/questions/17129018/…

– R zu
Nov 15 '18 at 18:09





stackoverflow.com/questions/17129018/…

– R zu
Nov 15 '18 at 18:09













@RzuThank you so much. That answer is good!

– Wei
Nov 16 '18 at 0:35





@RzuThank you so much. That answer is good!

– Wei
Nov 16 '18 at 0:35












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