How can I make seaborn distribution subplots in a loop?
I have a 5D array called data
for i in range(10):
sns.distplot(data[i,0,0,0], hist=False)
But I want to make them inside subplots instead. How can I do it?
Tried this:
plt.rc('figure', figsize=(4, 4))
fig=plt.figure()
fig, ax = plt.subplots(ncols=4, nrows=3)
for i in range(10):
ax[i].sns.distplot(data[i,0,0,0], hist=False)
plt.show()
This obviously doesn't work.
python numpy matplotlib seaborn
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
add a comment |
I have a 5D array called data
for i in range(10):
sns.distplot(data[i,0,0,0], hist=False)
But I want to make them inside subplots instead. How can I do it?
Tried this:
plt.rc('figure', figsize=(4, 4))
fig=plt.figure()
fig, ax = plt.subplots(ncols=4, nrows=3)
for i in range(10):
ax[i].sns.distplot(data[i,0,0,0], hist=False)
plt.show()
This obviously doesn't work.
python numpy matplotlib seaborn
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
add a comment |
I have a 5D array called data
for i in range(10):
sns.distplot(data[i,0,0,0], hist=False)
But I want to make them inside subplots instead. How can I do it?
Tried this:
plt.rc('figure', figsize=(4, 4))
fig=plt.figure()
fig, ax = plt.subplots(ncols=4, nrows=3)
for i in range(10):
ax[i].sns.distplot(data[i,0,0,0], hist=False)
plt.show()
This obviously doesn't work.
python numpy matplotlib seaborn
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
I have a 5D array called data
for i in range(10):
sns.distplot(data[i,0,0,0], hist=False)
But I want to make them inside subplots instead. How can I do it?
Tried this:
plt.rc('figure', figsize=(4, 4))
fig=plt.figure()
fig, ax = plt.subplots(ncols=4, nrows=3)
for i in range(10):
ax[i].sns.distplot(data[i,0,0,0], hist=False)
plt.show()
This obviously doesn't work.
python numpy matplotlib seaborn
python numpy matplotlib seaborn
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
asked Nov 14 '18 at 23:19
maximusdookumaximusdooku
1,48721445
1,48721445
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You would want to use the ax argument of the seaborn distplot function to supply an existing axes to it. Looping can be simplified by looping over the flattened array of axes.
fig, axes = plt.subplots(ncols=4, nrows=3)
for i, ax in zip(range(10), axes.flat):
sns.distplot(data[i,0,0,0], hist=False, ax=ax)
plt.show()
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
add a comment |
Specify which subplot each distplot should fall on:
f = plt.figure()
for i in range(10):
f.add_subplot(4, 3, i+1)
sns.distplot(data[i,0,0,0], hist=False)
plt.show()
answered Nov 14 '18 at 23:26
TimTim
1,767620
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You would want to use the ax argument of the seaborn distplot function to supply an existing axes to it. Looping can be simplified by looping over the flattened array of axes.
fig, axes = plt.subplots(ncols=4, nrows=3)
for i, ax in zip(range(10), axes.flat):
sns.distplot(data[i,0,0,0], hist=False, ax=ax)
plt.show()
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
add a comment |
You would want to use the ax argument of the seaborn distplot function to supply an existing axes to it. Looping can be simplified by looping over the flattened array of axes.
fig, axes = plt.subplots(ncols=4, nrows=3)
for i, ax in zip(range(10), axes.flat):
sns.distplot(data[i,0,0,0], hist=False, ax=ax)
plt.show()
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
add a comment |
You would want to use the ax argument of the seaborn distplot function to supply an existing axes to it. Looping can be simplified by looping over the flattened array of axes.
fig, axes = plt.subplots(ncols=4, nrows=3)
for i, ax in zip(range(10), axes.flat):
sns.distplot(data[i,0,0,0], hist=False, ax=ax)
plt.show()
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
You would want to use the ax argument of the seaborn distplot function to supply an existing axes to it. Looping can be simplified by looping over the flattened array of axes.
fig, axes = plt.subplots(ncols=4, nrows=3)
for i, ax in zip(range(10), axes.flat):
sns.distplot(data[i,0,0,0], hist=False, ax=ax)
plt.show()
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
answered Nov 14 '18 at 23:50
ImportanceOfBeingErnestImportanceOfBeingErnest
135k13151226
135k13151226
add a comment |
add a comment |
Specify which subplot each distplot should fall on:
f = plt.figure()
for i in range(10):
f.add_subplot(4, 3, i+1)
sns.distplot(data[i,0,0,0], hist=False)
plt.show()
answered Nov 14 '18 at 23:26
TimTim
1,767620
add a comment |
Specify which subplot each distplot should fall on:
f = plt.figure()
for i in range(10):
f.add_subplot(4, 3, i+1)
sns.distplot(data[i,0,0,0], hist=False)
plt.show()
answered Nov 14 '18 at 23:26
TimTim
1,767620
add a comment |
Specify which subplot each distplot should fall on:
f = plt.figure()
for i in range(10):
f.add_subplot(4, 3, i+1)
sns.distplot(data[i,0,0,0], hist=False)
plt.show()
answered Nov 14 '18 at 23:26
TimTim
1,767620
Specify which subplot each distplot should fall on:
f = plt.figure()
for i in range(10):
f.add_subplot(4, 3, i+1)
sns.distplot(data[i,0,0,0], hist=False)
plt.show()
answered Nov 14 '18 at 23:26
TimTim
1,767620
answered Nov 14 '18 at 23:26
TimTim
1,767620
answered Nov 14 '18 at 23:26
TimTim
1,767620
answered Nov 14 '18 at 23:26
TimTim
1,767620
1,767620
add a comment |
add a comment |
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