Sequelize query returns Promise. How to wait for query to return result?
0
I have two models with User belongsTo Status relationship. I am trying to track the changes made to the status column in the User record. In my hook I have:
afterUpdate: (instance, options) =>
if (instance.dataValues.statusId !== instance._previousDataValues.statusId)
const Track =
new_status: sequelize.models.Status.findById(instance.dataValues.statusId).then(status =>
console.log('1._____');
console.log(status.dataValues.name);
return status.dataValues.name;
)
console.log('2.____');
console.log(Track.new_status);
else
console.log('Status is not changed');
Output:
2.____
Promise
_bitField: 0,
_fulfillmentHandler0: undefined,
_rejectionHandler0: undefined,
_promise0: undefined,
_receiver0: undefined
Executing (default): SELECT "id", "name", "detail", "createdAt", "updatedAt" FROM "Statuses" AS "Status" WHERE "Status"."id" = 18;
1._____
Cancelled
I see that at console.log(Track.new_status) the querying is not yet completed and at console.log(status.dataValues.name) it rightly returns the status name. How to do I make it to wait until it complete the querying?
node.js orm sequelize.js sequelize-cli
asked Nov 14 '18 at 4:11
niaSniaS
387
add a comment |
0
I have two models with User belongsTo Status relationship. I am trying to track the changes made to the status column in the User record. In my hook I have:
afterUpdate: (instance, options) =>
if (instance.dataValues.statusId !== instance._previousDataValues.statusId)
const Track =
new_status: sequelize.models.Status.findById(instance.dataValues.statusId).then(status =>
console.log('1._____');
console.log(status.dataValues.name);
return status.dataValues.name;
)
console.log('2.____');
console.log(Track.new_status);
else
console.log('Status is not changed');
Output:
2.____
Promise
_bitField: 0,
_fulfillmentHandler0: undefined,
_rejectionHandler0: undefined,
_promise0: undefined,
_receiver0: undefined
Executing (default): SELECT "id", "name", "detail", "createdAt", "updatedAt" FROM "Statuses" AS "Status" WHERE "Status"."id" = 18;
1._____
Cancelled
I see that at console.log(Track.new_status) the querying is not yet completed and at console.log(status.dataValues.name) it rightly returns the status name. How to do I make it to wait until it complete the querying?
node.js orm sequelize.js sequelize-cli
asked Nov 14 '18 at 4:11
niaSniaS
387
Possible duplicate of How do I return the response from an asynchronous call?
– CertainPerformance
Nov 14 '18 at 4:27
3
Put everything inside the.thenor useawait
– CertainPerformance
Nov 14 '18 at 4:27
add a comment |
0
0
0
I have two models with User belongsTo Status relationship. I am trying to track the changes made to the status column in the User record. In my hook I have:
afterUpdate: (instance, options) =>
if (instance.dataValues.statusId !== instance._previousDataValues.statusId)
const Track =
new_status: sequelize.models.Status.findById(instance.dataValues.statusId).then(status =>
console.log('1._____');
console.log(status.dataValues.name);
return status.dataValues.name;
)
console.log('2.____');
console.log(Track.new_status);
else
console.log('Status is not changed');
Output:
2.____
Promise
_bitField: 0,
_fulfillmentHandler0: undefined,
_rejectionHandler0: undefined,
_promise0: undefined,
_receiver0: undefined
Executing (default): SELECT "id", "name", "detail", "createdAt", "updatedAt" FROM "Statuses" AS "Status" WHERE "Status"."id" = 18;
1._____
Cancelled
I see that at console.log(Track.new_status) the querying is not yet completed and at console.log(status.dataValues.name) it rightly returns the status name. How to do I make it to wait until it complete the querying?
node.js orm sequelize.js sequelize-cli
asked Nov 14 '18 at 4:11
niaSniaS
387
I have two models with User belongsTo Status relationship. I am trying to track the changes made to the status column in the User record. In my hook I have:
afterUpdate: (instance, options) =>
if (instance.dataValues.statusId !== instance._previousDataValues.statusId)
const Track =
new_status: sequelize.models.Status.findById(instance.dataValues.statusId).then(status =>
console.log('1._____');
console.log(status.dataValues.name);
return status.dataValues.name;
)
console.log('2.____');
console.log(Track.new_status);
else
console.log('Status is not changed');
Output:
2.____
Promise
_bitField: 0,
_fulfillmentHandler0: undefined,
_rejectionHandler0: undefined,
_promise0: undefined,
_receiver0: undefined
Executing (default): SELECT "id", "name", "detail", "createdAt", "updatedAt" FROM "Statuses" AS "Status" WHERE "Status"."id" = 18;
1._____
Cancelled
I see that at console.log(Track.new_status) the querying is not yet completed and at console.log(status.dataValues.name) it rightly returns the status name. How to do I make it to wait until it complete the querying?
node.js orm sequelize.js sequelize-cli
node.js orm sequelize.js sequelize-cli
asked Nov 14 '18 at 4:11
niaSniaS
387
asked Nov 14 '18 at 4:11
niaSniaS
387
asked Nov 14 '18 at 4:11
niaSniaS
387
asked Nov 14 '18 at 4:11
niaSniaS
387
asked Nov 14 '18 at 4:11
niaSniaS
387
387
Possible duplicate of How do I return the response from an asynchronous call?
– CertainPerformance
Nov 14 '18 at 4:27
3
Put everything inside the.thenor useawait
– CertainPerformance
Nov 14 '18 at 4:27
add a comment |
Possible duplicate of How do I return the response from an asynchronous call?
– CertainPerformance
Nov 14 '18 at 4:27
3
Put everything inside the.thenor useawait
– CertainPerformance
Nov 14 '18 at 4:27
Possible duplicate of How do I return the response from an asynchronous call?
– CertainPerformance
Nov 14 '18 at 4:27
Possible duplicate of How do I return the response from an asynchronous call?
– CertainPerformance
Nov 14 '18 at 4:27
3
3
Put everything inside the
.then or use await– CertainPerformance
Nov 14 '18 at 4:27
Put everything inside the
.then or use await– CertainPerformance
Nov 14 '18 at 4:27
add a comment |
1 Answer
1
active
oldest
votes
1
Using async/await:
async function getTrack(trackID)
const track = await Track.findByPk(trackID);
console.log('track', track);
Using Promises:
function getTrack(trackID)
const track = Track.findByPk(trackID)
.then((track) =>
console.log('track', track);
);
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
Thanks, as perCertainPerformancesuggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)
– niaS
Nov 15 '18 at 6:26
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Using async/await:
async function getTrack(trackID)
const track = await Track.findByPk(trackID);
console.log('track', track);
Using Promises:
function getTrack(trackID)
const track = Track.findByPk(trackID)
.then((track) =>
console.log('track', track);
);
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
Thanks, as perCertainPerformancesuggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)
– niaS
Nov 15 '18 at 6:26
add a comment |
1
Using async/await:
async function getTrack(trackID)
const track = await Track.findByPk(trackID);
console.log('track', track);
Using Promises:
function getTrack(trackID)
const track = Track.findByPk(trackID)
.then((track) =>
console.log('track', track);
);
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
Thanks, as perCertainPerformancesuggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)
– niaS
Nov 15 '18 at 6:26
add a comment |
1
1
1
Using async/await:
async function getTrack(trackID)
const track = await Track.findByPk(trackID);
console.log('track', track);
Using Promises:
function getTrack(trackID)
const track = Track.findByPk(trackID)
.then((track) =>
console.log('track', track);
);
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
Using async/await:
async function getTrack(trackID)
const track = await Track.findByPk(trackID);
console.log('track', track);
Using Promises:
function getTrack(trackID)
const track = Track.findByPk(trackID)
.then((track) =>
console.log('track', track);
);
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
answered Nov 14 '18 at 16:22
doublesharpdoublesharp
19.4k33659
19.4k33659
Thanks, as perCertainPerformancesuggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)
– niaS
Nov 15 '18 at 6:26
add a comment |
Thanks, as perCertainPerformancesuggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)
– niaS
Nov 15 '18 at 6:26
Thanks, as per
CertainPerformance suggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)– niaS
Nov 15 '18 at 6:26
Thanks, as per
CertainPerformance suggestion, I used await but didn't post here. It is same as your solution. So, I'll mark it solved. Thank you for the answer :)– niaS
Nov 15 '18 at 6:26
add a comment |
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Possible duplicate of How do I return the response from an asynchronous call?
– CertainPerformance
Nov 14 '18 at 4:27
3
Put everything inside the
.thenor useawait– CertainPerformance
Nov 14 '18 at 4:27