java- Full text inverted index defining a word










-1















I am working on a simple full text inverted index trying to build an index of words that I extract from PDF files. I am using PDFBox library to achieve this.



However, I would like to know how does one define a definition of word to index.The way my indexing works is define every word with a space is a word token. For example,



This string, is a code.


In this case: the index table would contain



This
string,
is
a
code.


The flaw here is for like string, , it comes with a comma where I think string would just be sufficient enough because nobody searches string, or code.



Back to my question, is there a specific rule there I could use to define my word token in a way to prevent this kind of issue with what I have ?



Code:



File folder = new File("D:\PDF1");
File listOfFiles = folder.listFiles();

for (File file : listOfFiles)
if (file.isFile())
HashSet<String> uniqueWords = new HashSet<>();
String path = "D:\PDF1\" + file.getName();
try (PDDocument document = PDDocument.load(new File(path)))
if (!document.isEncrypted())
PDFTextStripper tStripper = new PDFTextStripper();
String pdfFileInText = tStripper.getText(document);
String lines = pdfFileInText.split("\r?\n");
for(String line : lines)
String words = line.split(" ");
for (String word : words)
uniqueWords.add(word);




catch (IOException e)
System.err.println("Exception while trying to read pdf document - " + e);












share|improve this question
























  • why don' t you replace , with a "" ?

    – Scary Wombat
    Nov 14 '18 at 1:54











  • @ScaryWombat What do you mean? Sorry, I'm a bit blur on this regular expression thing.

    – Daredevil
    Nov 14 '18 at 1:54











  • let's see, a word is a String, a String has a method replace - so replace "," with "" - this is not regex. Then add it to your List

    – Scary Wombat
    Nov 14 '18 at 1:56











  • I see but would that contradict some special case like there is a sentence with date 15/12/2018 or f(x) = 2x +3y where it would be ideal to classify these as 2 words considering they are not separated by spaces.

    – Daredevil
    Nov 14 '18 at 1:58











  • The logic is yours, in my example all I am replacing is comma

    – Scary Wombat
    Nov 14 '18 at 1:58
















-1















I am working on a simple full text inverted index trying to build an index of words that I extract from PDF files. I am using PDFBox library to achieve this.



However, I would like to know how does one define a definition of word to index.The way my indexing works is define every word with a space is a word token. For example,



This string, is a code.


In this case: the index table would contain



This
string,
is
a
code.


The flaw here is for like string, , it comes with a comma where I think string would just be sufficient enough because nobody searches string, or code.



Back to my question, is there a specific rule there I could use to define my word token in a way to prevent this kind of issue with what I have ?



Code:



File folder = new File("D:\PDF1");
File listOfFiles = folder.listFiles();

for (File file : listOfFiles)
if (file.isFile())
HashSet<String> uniqueWords = new HashSet<>();
String path = "D:\PDF1\" + file.getName();
try (PDDocument document = PDDocument.load(new File(path)))
if (!document.isEncrypted())
PDFTextStripper tStripper = new PDFTextStripper();
String pdfFileInText = tStripper.getText(document);
String lines = pdfFileInText.split("\r?\n");
for(String line : lines)
String words = line.split(" ");
for (String word : words)
uniqueWords.add(word);




catch (IOException e)
System.err.println("Exception while trying to read pdf document - " + e);












share|improve this question
























  • why don' t you replace , with a "" ?

    – Scary Wombat
    Nov 14 '18 at 1:54











  • @ScaryWombat What do you mean? Sorry, I'm a bit blur on this regular expression thing.

    – Daredevil
    Nov 14 '18 at 1:54











  • let's see, a word is a String, a String has a method replace - so replace "," with "" - this is not regex. Then add it to your List

    – Scary Wombat
    Nov 14 '18 at 1:56











  • I see but would that contradict some special case like there is a sentence with date 15/12/2018 or f(x) = 2x +3y where it would be ideal to classify these as 2 words considering they are not separated by spaces.

    – Daredevil
    Nov 14 '18 at 1:58











  • The logic is yours, in my example all I am replacing is comma

    – Scary Wombat
    Nov 14 '18 at 1:58














-1












-1








-1








I am working on a simple full text inverted index trying to build an index of words that I extract from PDF files. I am using PDFBox library to achieve this.



However, I would like to know how does one define a definition of word to index.The way my indexing works is define every word with a space is a word token. For example,



This string, is a code.


In this case: the index table would contain



This
string,
is
a
code.


The flaw here is for like string, , it comes with a comma where I think string would just be sufficient enough because nobody searches string, or code.



Back to my question, is there a specific rule there I could use to define my word token in a way to prevent this kind of issue with what I have ?



Code:



File folder = new File("D:\PDF1");
File listOfFiles = folder.listFiles();

for (File file : listOfFiles)
if (file.isFile())
HashSet<String> uniqueWords = new HashSet<>();
String path = "D:\PDF1\" + file.getName();
try (PDDocument document = PDDocument.load(new File(path)))
if (!document.isEncrypted())
PDFTextStripper tStripper = new PDFTextStripper();
String pdfFileInText = tStripper.getText(document);
String lines = pdfFileInText.split("\r?\n");
for(String line : lines)
String words = line.split(" ");
for (String word : words)
uniqueWords.add(word);




catch (IOException e)
System.err.println("Exception while trying to read pdf document - " + e);












share|improve this question
















I am working on a simple full text inverted index trying to build an index of words that I extract from PDF files. I am using PDFBox library to achieve this.



However, I would like to know how does one define a definition of word to index.The way my indexing works is define every word with a space is a word token. For example,



This string, is a code.


In this case: the index table would contain



This
string,
is
a
code.


The flaw here is for like string, , it comes with a comma where I think string would just be sufficient enough because nobody searches string, or code.



Back to my question, is there a specific rule there I could use to define my word token in a way to prevent this kind of issue with what I have ?



Code:



File folder = new File("D:\PDF1");
File listOfFiles = folder.listFiles();

for (File file : listOfFiles)
if (file.isFile())
HashSet<String> uniqueWords = new HashSet<>();
String path = "D:\PDF1\" + file.getName();
try (PDDocument document = PDDocument.load(new File(path)))
if (!document.isEncrypted())
PDFTextStripper tStripper = new PDFTextStripper();
String pdfFileInText = tStripper.getText(document);
String lines = pdfFileInText.split("\r?\n");
for(String line : lines)
String words = line.split(" ");
for (String word : words)
uniqueWords.add(word);




catch (IOException e)
System.err.println("Exception while trying to read pdf document - " + e);









java pdfbox






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 2:04









GBlodgett

10.1k42035




10.1k42035










asked Nov 14 '18 at 1:51









DaredevilDaredevil

19011




19011












  • why don' t you replace , with a "" ?

    – Scary Wombat
    Nov 14 '18 at 1:54











  • @ScaryWombat What do you mean? Sorry, I'm a bit blur on this regular expression thing.

    – Daredevil
    Nov 14 '18 at 1:54











  • let's see, a word is a String, a String has a method replace - so replace "," with "" - this is not regex. Then add it to your List

    – Scary Wombat
    Nov 14 '18 at 1:56











  • I see but would that contradict some special case like there is a sentence with date 15/12/2018 or f(x) = 2x +3y where it would be ideal to classify these as 2 words considering they are not separated by spaces.

    – Daredevil
    Nov 14 '18 at 1:58











  • The logic is yours, in my example all I am replacing is comma

    – Scary Wombat
    Nov 14 '18 at 1:58


















  • why don' t you replace , with a "" ?

    – Scary Wombat
    Nov 14 '18 at 1:54











  • @ScaryWombat What do you mean? Sorry, I'm a bit blur on this regular expression thing.

    – Daredevil
    Nov 14 '18 at 1:54











  • let's see, a word is a String, a String has a method replace - so replace "," with "" - this is not regex. Then add it to your List

    – Scary Wombat
    Nov 14 '18 at 1:56











  • I see but would that contradict some special case like there is a sentence with date 15/12/2018 or f(x) = 2x +3y where it would be ideal to classify these as 2 words considering they are not separated by spaces.

    – Daredevil
    Nov 14 '18 at 1:58











  • The logic is yours, in my example all I am replacing is comma

    – Scary Wombat
    Nov 14 '18 at 1:58

















why don' t you replace , with a "" ?

– Scary Wombat
Nov 14 '18 at 1:54





why don' t you replace , with a "" ?

– Scary Wombat
Nov 14 '18 at 1:54













@ScaryWombat What do you mean? Sorry, I'm a bit blur on this regular expression thing.

– Daredevil
Nov 14 '18 at 1:54





@ScaryWombat What do you mean? Sorry, I'm a bit blur on this regular expression thing.

– Daredevil
Nov 14 '18 at 1:54













let's see, a word is a String, a String has a method replace - so replace "," with "" - this is not regex. Then add it to your List

– Scary Wombat
Nov 14 '18 at 1:56





let's see, a word is a String, a String has a method replace - so replace "," with "" - this is not regex. Then add it to your List

– Scary Wombat
Nov 14 '18 at 1:56













I see but would that contradict some special case like there is a sentence with date 15/12/2018 or f(x) = 2x +3y where it would be ideal to classify these as 2 words considering they are not separated by spaces.

– Daredevil
Nov 14 '18 at 1:58





I see but would that contradict some special case like there is a sentence with date 15/12/2018 or f(x) = 2x +3y where it would be ideal to classify these as 2 words considering they are not separated by spaces.

– Daredevil
Nov 14 '18 at 1:58













The logic is yours, in my example all I am replacing is comma

– Scary Wombat
Nov 14 '18 at 1:58






The logic is yours, in my example all I am replacing is comma

– Scary Wombat
Nov 14 '18 at 1:58













2 Answers
2






active

oldest

votes


















1














Yes. You can use replaceAll method to get rid of non-word characters like this:



uniqueWords.add(word.replaceAll("([\W]+$)|(^[\W]+)", "")); 





share|improve this answer

























  • what is \W? I am confused

    – Daredevil
    Nov 14 '18 at 2:14











  • non-word characters, W should be a capital one

    – Aleksandr Gromov
    Nov 14 '18 at 2:15












  • But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

    – Daredevil
    Nov 14 '18 at 2:18











  • Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

    – Aleksandr Gromov
    Nov 14 '18 at 2:42












  • There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

    – Daredevil
    Nov 14 '18 at 2:44


















2














If you wanted to remove all punctuation you could do:



for(String word : words) 
uniqueWords.add(word.replaceAll("[.,!?]", ""));



Which will replace all periods, commas, exclamation marks, and question marks.




If you also want to get rid of quotes you can do:



uniqueWords.add(word.replaceAll("[.,?!"]", "")





share|improve this answer

























  • What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

    – Daredevil
    Nov 14 '18 at 1:56






  • 1





    Which will replace all periods, commas, exclamation marks, and question marks

    – Scary Wombat
    Nov 14 '18 at 1:57











  • @Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

    – GBlodgett
    Nov 14 '18 at 1:58











  • Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

    – Daredevil
    Nov 14 '18 at 2:14











  • @Daredevil What do you mean? Replace animal with what?

    – GBlodgett
    Nov 14 '18 at 2:15










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Yes. You can use replaceAll method to get rid of non-word characters like this:



uniqueWords.add(word.replaceAll("([\W]+$)|(^[\W]+)", "")); 





share|improve this answer

























  • what is \W? I am confused

    – Daredevil
    Nov 14 '18 at 2:14











  • non-word characters, W should be a capital one

    – Aleksandr Gromov
    Nov 14 '18 at 2:15












  • But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

    – Daredevil
    Nov 14 '18 at 2:18











  • Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

    – Aleksandr Gromov
    Nov 14 '18 at 2:42












  • There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

    – Daredevil
    Nov 14 '18 at 2:44















1














Yes. You can use replaceAll method to get rid of non-word characters like this:



uniqueWords.add(word.replaceAll("([\W]+$)|(^[\W]+)", "")); 





share|improve this answer

























  • what is \W? I am confused

    – Daredevil
    Nov 14 '18 at 2:14











  • non-word characters, W should be a capital one

    – Aleksandr Gromov
    Nov 14 '18 at 2:15












  • But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

    – Daredevil
    Nov 14 '18 at 2:18











  • Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

    – Aleksandr Gromov
    Nov 14 '18 at 2:42












  • There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

    – Daredevil
    Nov 14 '18 at 2:44













1












1








1







Yes. You can use replaceAll method to get rid of non-word characters like this:



uniqueWords.add(word.replaceAll("([\W]+$)|(^[\W]+)", "")); 





share|improve this answer















Yes. You can use replaceAll method to get rid of non-word characters like this:



uniqueWords.add(word.replaceAll("([\W]+$)|(^[\W]+)", "")); 






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 4:01

























answered Nov 14 '18 at 2:14









Aleksandr GromovAleksandr Gromov

463




463












  • what is \W? I am confused

    – Daredevil
    Nov 14 '18 at 2:14











  • non-word characters, W should be a capital one

    – Aleksandr Gromov
    Nov 14 '18 at 2:15












  • But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

    – Daredevil
    Nov 14 '18 at 2:18











  • Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

    – Aleksandr Gromov
    Nov 14 '18 at 2:42












  • There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

    – Daredevil
    Nov 14 '18 at 2:44

















  • what is \W? I am confused

    – Daredevil
    Nov 14 '18 at 2:14











  • non-word characters, W should be a capital one

    – Aleksandr Gromov
    Nov 14 '18 at 2:15












  • But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

    – Daredevil
    Nov 14 '18 at 2:18











  • Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

    – Aleksandr Gromov
    Nov 14 '18 at 2:42












  • There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

    – Daredevil
    Nov 14 '18 at 2:44
















what is \W? I am confused

– Daredevil
Nov 14 '18 at 2:14





what is \W? I am confused

– Daredevil
Nov 14 '18 at 2:14













non-word characters, W should be a capital one

– Aleksandr Gromov
Nov 14 '18 at 2:15






non-word characters, W should be a capital one

– Aleksandr Gromov
Nov 14 '18 at 2:15














But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

– Daredevil
Nov 14 '18 at 2:18





But there's gonna be a problem say I have a date 10/12/2018 and I have to include this whole in my index then it's gonna omit the "/" which I don't want

– Daredevil
Nov 14 '18 at 2:18













Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

– Aleksandr Gromov
Nov 14 '18 at 2:42






Edited. I added exclusion, you can add exclusions in this section [^/]. So now, it will remove all non-word characters except those which are provided in [^/] section

– Aleksandr Gromov
Nov 14 '18 at 2:42














There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

– Daredevil
Nov 14 '18 at 2:44





There is a problem. If I have animal. then i would get animal which is fine. But what if I have 69.4 and i would like it in the same form, it would then omit the dot and becomes 694

– Daredevil
Nov 14 '18 at 2:44













2














If you wanted to remove all punctuation you could do:



for(String word : words) 
uniqueWords.add(word.replaceAll("[.,!?]", ""));



Which will replace all periods, commas, exclamation marks, and question marks.




If you also want to get rid of quotes you can do:



uniqueWords.add(word.replaceAll("[.,?!"]", "")





share|improve this answer

























  • What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

    – Daredevil
    Nov 14 '18 at 1:56






  • 1





    Which will replace all periods, commas, exclamation marks, and question marks

    – Scary Wombat
    Nov 14 '18 at 1:57











  • @Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

    – GBlodgett
    Nov 14 '18 at 1:58











  • Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

    – Daredevil
    Nov 14 '18 at 2:14











  • @Daredevil What do you mean? Replace animal with what?

    – GBlodgett
    Nov 14 '18 at 2:15















2














If you wanted to remove all punctuation you could do:



for(String word : words) 
uniqueWords.add(word.replaceAll("[.,!?]", ""));



Which will replace all periods, commas, exclamation marks, and question marks.




If you also want to get rid of quotes you can do:



uniqueWords.add(word.replaceAll("[.,?!"]", "")





share|improve this answer

























  • What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

    – Daredevil
    Nov 14 '18 at 1:56






  • 1





    Which will replace all periods, commas, exclamation marks, and question marks

    – Scary Wombat
    Nov 14 '18 at 1:57











  • @Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

    – GBlodgett
    Nov 14 '18 at 1:58











  • Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

    – Daredevil
    Nov 14 '18 at 2:14











  • @Daredevil What do you mean? Replace animal with what?

    – GBlodgett
    Nov 14 '18 at 2:15













2












2








2







If you wanted to remove all punctuation you could do:



for(String word : words) 
uniqueWords.add(word.replaceAll("[.,!?]", ""));



Which will replace all periods, commas, exclamation marks, and question marks.




If you also want to get rid of quotes you can do:



uniqueWords.add(word.replaceAll("[.,?!"]", "")





share|improve this answer















If you wanted to remove all punctuation you could do:



for(String word : words) 
uniqueWords.add(word.replaceAll("[.,!?]", ""));



Which will replace all periods, commas, exclamation marks, and question marks.




If you also want to get rid of quotes you can do:



uniqueWords.add(word.replaceAll("[.,?!"]", "")






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 2:26

























answered Nov 14 '18 at 1:54









GBlodgettGBlodgett

10.1k42035




10.1k42035












  • What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

    – Daredevil
    Nov 14 '18 at 1:56






  • 1





    Which will replace all periods, commas, exclamation marks, and question marks

    – Scary Wombat
    Nov 14 '18 at 1:57











  • @Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

    – GBlodgett
    Nov 14 '18 at 1:58











  • Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

    – Daredevil
    Nov 14 '18 at 2:14











  • @Daredevil What do you mean? Replace animal with what?

    – GBlodgett
    Nov 14 '18 at 2:15

















  • What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

    – Daredevil
    Nov 14 '18 at 1:56






  • 1





    Which will replace all periods, commas, exclamation marks, and question marks

    – Scary Wombat
    Nov 14 '18 at 1:57











  • @Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

    – GBlodgett
    Nov 14 '18 at 1:58











  • Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

    – Daredevil
    Nov 14 '18 at 2:14











  • @Daredevil What do you mean? Replace animal with what?

    – GBlodgett
    Nov 14 '18 at 2:15
















What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

– Daredevil
Nov 14 '18 at 1:56





What does it do? But what if my sentence contains say 11/2/2018 and I would like it as a whole as a word. It would eliminate it right?

– Daredevil
Nov 14 '18 at 1:56




1




1





Which will replace all periods, commas, exclamation marks, and question marks

– Scary Wombat
Nov 14 '18 at 1:57





Which will replace all periods, commas, exclamation marks, and question marks

– Scary Wombat
Nov 14 '18 at 1:57













@Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

– GBlodgett
Nov 14 '18 at 1:58





@Daredevil No it will not. Try it for yourself: System.out.println("10/2/18".replaceAll("[.,!?]", ""));

– GBlodgett
Nov 14 '18 at 1:58













Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

– Daredevil
Nov 14 '18 at 2:14





Would it be possible to replace like "animal" to read it as animal? I tried including it as well but it wouldn't take the argument

– Daredevil
Nov 14 '18 at 2:14













@Daredevil What do you mean? Replace animal with what?

– GBlodgett
Nov 14 '18 at 2:15





@Daredevil What do you mean? Replace animal with what?

– GBlodgett
Nov 14 '18 at 2:15

















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