How to quickly apply over Document Term Matrix in R
I am working on a project that requires me to iterate over a Document Term Matrix, converting all non-zero values to 1 and keeping zero values at zero. The function I'm using now takes forever to run, and I would like help optimizing the code.
My code as it is right now is
convert_counts <- function(x)
x <- ifelse(x > 0, 1, 0)
x <- factor(x, levels = c(0, 1),
labels = c("No", "Yes"))
data_exp <- apply(data_dtm, 2, convert_counts)
Where data_dtm is a large Document Term Matrix.
r text-mining
add a comment |
I am working on a project that requires me to iterate over a Document Term Matrix, converting all non-zero values to 1 and keeping zero values at zero. The function I'm using now takes forever to run, and I would like help optimizing the code.
My code as it is right now is
convert_counts <- function(x)
x <- ifelse(x > 0, 1, 0)
x <- factor(x, levels = c(0, 1),
labels = c("No", "Yes"))
data_exp <- apply(data_dtm, 2, convert_counts)
Where data_dtm is a large Document Term Matrix.
r text-mining
I hope this helps you : stackoverflow.com/questions/12835942/…
– Carles Sans Fuentes
Nov 14 '18 at 16:28
add a comment |
I am working on a project that requires me to iterate over a Document Term Matrix, converting all non-zero values to 1 and keeping zero values at zero. The function I'm using now takes forever to run, and I would like help optimizing the code.
My code as it is right now is
convert_counts <- function(x)
x <- ifelse(x > 0, 1, 0)
x <- factor(x, levels = c(0, 1),
labels = c("No", "Yes"))
data_exp <- apply(data_dtm, 2, convert_counts)
Where data_dtm is a large Document Term Matrix.
r text-mining
I am working on a project that requires me to iterate over a Document Term Matrix, converting all non-zero values to 1 and keeping zero values at zero. The function I'm using now takes forever to run, and I would like help optimizing the code.
My code as it is right now is
convert_counts <- function(x)
x <- ifelse(x > 0, 1, 0)
x <- factor(x, levels = c(0, 1),
labels = c("No", "Yes"))
data_exp <- apply(data_dtm, 2, convert_counts)
Where data_dtm is a large Document Term Matrix.
r text-mining
r text-mining
edited Nov 14 '18 at 16:16
Griffin Barich
asked Nov 14 '18 at 15:53
Griffin BarichGriffin Barich
32
32
I hope this helps you : stackoverflow.com/questions/12835942/…
– Carles Sans Fuentes
Nov 14 '18 at 16:28
add a comment |
I hope this helps you : stackoverflow.com/questions/12835942/…
– Carles Sans Fuentes
Nov 14 '18 at 16:28
I hope this helps you : stackoverflow.com/questions/12835942/…
– Carles Sans Fuentes
Nov 14 '18 at 16:28
I hope this helps you : stackoverflow.com/questions/12835942/…
– Carles Sans Fuentes
Nov 14 '18 at 16:28
add a comment |
1 Answer
1
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votes
The function you have transforms a sparse matrix to a full character matrix. If you have a large document term matrix this will result in long running times and a good chance of getting a memory error. Replacing values in a sparse matrix can be done quickly if you make use of how the matrix is built. A sparse matrix values are stored in the v (values) part of the matrix. See ?slam::simple_triplet_matrix.
Using any of the apply family on a sparse matrix, without using functions that are designed to work with a sparse matrix will turn it into a normal (dense) matrix. With accordingly long run times and memory issues.
To change all values different from 0 in your case, just use the following:
data_dtm$v[data_dtm$v > 0] <- 1inspect(data_dtm) # show first 10 columns and rows
This replaces all the values to 1 and keeps the data as a document term matrix (aka nice and sparse).
Depending on your follow up data analysis you really should make use of sparse matrix functions. If you want to transform a large document term matrix into a data.frame or data.table you have a good chance of running out of memory.
For any follow up questions, please include a reproducible example and an expected output.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The function you have transforms a sparse matrix to a full character matrix. If you have a large document term matrix this will result in long running times and a good chance of getting a memory error. Replacing values in a sparse matrix can be done quickly if you make use of how the matrix is built. A sparse matrix values are stored in the v (values) part of the matrix. See ?slam::simple_triplet_matrix.
Using any of the apply family on a sparse matrix, without using functions that are designed to work with a sparse matrix will turn it into a normal (dense) matrix. With accordingly long run times and memory issues.
To change all values different from 0 in your case, just use the following:
data_dtm$v[data_dtm$v > 0] <- 1inspect(data_dtm) # show first 10 columns and rows
This replaces all the values to 1 and keeps the data as a document term matrix (aka nice and sparse).
Depending on your follow up data analysis you really should make use of sparse matrix functions. If you want to transform a large document term matrix into a data.frame or data.table you have a good chance of running out of memory.
For any follow up questions, please include a reproducible example and an expected output.
add a comment |
The function you have transforms a sparse matrix to a full character matrix. If you have a large document term matrix this will result in long running times and a good chance of getting a memory error. Replacing values in a sparse matrix can be done quickly if you make use of how the matrix is built. A sparse matrix values are stored in the v (values) part of the matrix. See ?slam::simple_triplet_matrix.
Using any of the apply family on a sparse matrix, without using functions that are designed to work with a sparse matrix will turn it into a normal (dense) matrix. With accordingly long run times and memory issues.
To change all values different from 0 in your case, just use the following:
data_dtm$v[data_dtm$v > 0] <- 1inspect(data_dtm) # show first 10 columns and rows
This replaces all the values to 1 and keeps the data as a document term matrix (aka nice and sparse).
Depending on your follow up data analysis you really should make use of sparse matrix functions. If you want to transform a large document term matrix into a data.frame or data.table you have a good chance of running out of memory.
For any follow up questions, please include a reproducible example and an expected output.
add a comment |
The function you have transforms a sparse matrix to a full character matrix. If you have a large document term matrix this will result in long running times and a good chance of getting a memory error. Replacing values in a sparse matrix can be done quickly if you make use of how the matrix is built. A sparse matrix values are stored in the v (values) part of the matrix. See ?slam::simple_triplet_matrix.
Using any of the apply family on a sparse matrix, without using functions that are designed to work with a sparse matrix will turn it into a normal (dense) matrix. With accordingly long run times and memory issues.
To change all values different from 0 in your case, just use the following:
data_dtm$v[data_dtm$v > 0] <- 1inspect(data_dtm) # show first 10 columns and rows
This replaces all the values to 1 and keeps the data as a document term matrix (aka nice and sparse).
Depending on your follow up data analysis you really should make use of sparse matrix functions. If you want to transform a large document term matrix into a data.frame or data.table you have a good chance of running out of memory.
For any follow up questions, please include a reproducible example and an expected output.
The function you have transforms a sparse matrix to a full character matrix. If you have a large document term matrix this will result in long running times and a good chance of getting a memory error. Replacing values in a sparse matrix can be done quickly if you make use of how the matrix is built. A sparse matrix values are stored in the v (values) part of the matrix. See ?slam::simple_triplet_matrix.
Using any of the apply family on a sparse matrix, without using functions that are designed to work with a sparse matrix will turn it into a normal (dense) matrix. With accordingly long run times and memory issues.
To change all values different from 0 in your case, just use the following:
data_dtm$v[data_dtm$v > 0] <- 1inspect(data_dtm) # show first 10 columns and rows
This replaces all the values to 1 and keeps the data as a document term matrix (aka nice and sparse).
Depending on your follow up data analysis you really should make use of sparse matrix functions. If you want to transform a large document term matrix into a data.frame or data.table you have a good chance of running out of memory.
For any follow up questions, please include a reproducible example and an expected output.
answered Nov 14 '18 at 18:59
phiverphiver
13.5k92835
13.5k92835
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I hope this helps you : stackoverflow.com/questions/12835942/…
– Carles Sans Fuentes
Nov 14 '18 at 16:28