parse json response into name value pair
1
I have a json string , and i want it to be converted into name value pair json string.
My actual string:
"payload":["YearlylCostPercentage":"4.6",
"TotalRepayment":"120000","PropertyMarketValue":"100000","productname":"Standard","PaymentFrequency":"Monthly","NumberOfTerms":"60","NotaryName":"Notary","NotaryEmail":"raj234eu222222222.sen@yahoo.com","NotaryContactNumber":"0234241729","NotaryAdressLine2":"1112 CM The Hag","NotaryAdressLine1":"Valkenboslaan 110","nominalInterestRate":"4.5","MonthlyPayment":"600","MonthlyInterestAmount":"300","loanUtilizationDate":"12-1-2019","loanPurpose":"Loan","loanMaturityDate":"12-2-2019","LoanDuration":"5","loanAmount":"100000","KadasterLocation":"Amsterdam","InterestFixationProvision":"1.0","HandlingCost":"900","FixedInterestyear":"2.0","firstPaymentDate":"12-2-2019","FirstMonthlyPayment":"700","effectiveInterestRate":"4.7","DepartmentName":"Dev","CustomerDetails":["CustomerSalutation":"Geen titulatuur gewenst","CustomerName":"Eqaavq","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345", "CustomerSalutation":"Mevrouw","CustomerName":"Eqaavq-col Fpcysfptp","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345"],"city":"Amsterdam","BorrowedRatio":"1.4","AdvisorName":"Raju Sen","AdvisorContact":"2123123312","AdviseCost":"1000"]';
expected output :
"payload":{
"name" : "YearlylCostPercentage",
"value":"4.6"
,
"name":"TotalRepayment",
"value":"120000"
apex json
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
|
show 4 more comments
1
I have a json string , and i want it to be converted into name value pair json string.
My actual string:
"payload":["YearlylCostPercentage":"4.6",
"TotalRepayment":"120000","PropertyMarketValue":"100000","productname":"Standard","PaymentFrequency":"Monthly","NumberOfTerms":"60","NotaryName":"Notary","NotaryEmail":"raj234eu222222222.sen@yahoo.com","NotaryContactNumber":"0234241729","NotaryAdressLine2":"1112 CM The Hag","NotaryAdressLine1":"Valkenboslaan 110","nominalInterestRate":"4.5","MonthlyPayment":"600","MonthlyInterestAmount":"300","loanUtilizationDate":"12-1-2019","loanPurpose":"Loan","loanMaturityDate":"12-2-2019","LoanDuration":"5","loanAmount":"100000","KadasterLocation":"Amsterdam","InterestFixationProvision":"1.0","HandlingCost":"900","FixedInterestyear":"2.0","firstPaymentDate":"12-2-2019","FirstMonthlyPayment":"700","effectiveInterestRate":"4.7","DepartmentName":"Dev","CustomerDetails":["CustomerSalutation":"Geen titulatuur gewenst","CustomerName":"Eqaavq","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345", "CustomerSalutation":"Mevrouw","CustomerName":"Eqaavq-col Fpcysfptp","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345"],"city":"Amsterdam","BorrowedRatio":"1.4","AdvisorName":"Raju Sen","AdvisorContact":"2123123312","AdviseCost":"1000"]';
expected output :
"payload":{
"name" : "YearlylCostPercentage",
"value":"4.6"
,
"name":"TotalRepayment",
"value":"120000"
apex json
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
1
That's basically JSON abuse. Why do you want/need it in this format?
– sfdcfox
Nov 14 '18 at 13:53
3
Seems like this might be an X-Y problem. What will performing this transformation do for you? What ends up using this JSON? Is there a reason why you can't simply useJSON.deserialize()orJSON.deserializeUntyped()?
– Derek F
Nov 14 '18 at 13:55
yeah, its an abuse, we are trying to connect with one of the services , they want the request body to have this format , so we can't use it as it is, we cant ask them to handle this from their end too.
– Raju Sen
Nov 14 '18 at 14:11
Can we use json.createParser to form this output, iterating every attribute?
– Raju Sen
Nov 14 '18 at 14:16
1
Okay, just realized your JSON expected output is invalid JSON. Are you sure that's correct?
– sfdcfox
Nov 14 '18 at 14:20
|
show 4 more comments
1
1
1
1
I have a json string , and i want it to be converted into name value pair json string.
My actual string:
"payload":["YearlylCostPercentage":"4.6",
"TotalRepayment":"120000","PropertyMarketValue":"100000","productname":"Standard","PaymentFrequency":"Monthly","NumberOfTerms":"60","NotaryName":"Notary","NotaryEmail":"raj234eu222222222.sen@yahoo.com","NotaryContactNumber":"0234241729","NotaryAdressLine2":"1112 CM The Hag","NotaryAdressLine1":"Valkenboslaan 110","nominalInterestRate":"4.5","MonthlyPayment":"600","MonthlyInterestAmount":"300","loanUtilizationDate":"12-1-2019","loanPurpose":"Loan","loanMaturityDate":"12-2-2019","LoanDuration":"5","loanAmount":"100000","KadasterLocation":"Amsterdam","InterestFixationProvision":"1.0","HandlingCost":"900","FixedInterestyear":"2.0","firstPaymentDate":"12-2-2019","FirstMonthlyPayment":"700","effectiveInterestRate":"4.7","DepartmentName":"Dev","CustomerDetails":["CustomerSalutation":"Geen titulatuur gewenst","CustomerName":"Eqaavq","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345", "CustomerSalutation":"Mevrouw","CustomerName":"Eqaavq-col Fpcysfptp","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345"],"city":"Amsterdam","BorrowedRatio":"1.4","AdvisorName":"Raju Sen","AdvisorContact":"2123123312","AdviseCost":"1000"]';
expected output :
"payload":{
"name" : "YearlylCostPercentage",
"value":"4.6"
,
"name":"TotalRepayment",
"value":"120000"
apex json
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
I have a json string , and i want it to be converted into name value pair json string.
My actual string:
"payload":["YearlylCostPercentage":"4.6",
"TotalRepayment":"120000","PropertyMarketValue":"100000","productname":"Standard","PaymentFrequency":"Monthly","NumberOfTerms":"60","NotaryName":"Notary","NotaryEmail":"raj234eu222222222.sen@yahoo.com","NotaryContactNumber":"0234241729","NotaryAdressLine2":"1112 CM The Hag","NotaryAdressLine1":"Valkenboslaan 110","nominalInterestRate":"4.5","MonthlyPayment":"600","MonthlyInterestAmount":"300","loanUtilizationDate":"12-1-2019","loanPurpose":"Loan","loanMaturityDate":"12-2-2019","LoanDuration":"5","loanAmount":"100000","KadasterLocation":"Amsterdam","InterestFixationProvision":"1.0","HandlingCost":"900","FixedInterestyear":"2.0","firstPaymentDate":"12-2-2019","FirstMonthlyPayment":"700","effectiveInterestRate":"4.7","DepartmentName":"Dev","CustomerDetails":["CustomerSalutation":"Geen titulatuur gewenst","CustomerName":"Eqaavq","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345", "CustomerSalutation":"Mevrouw","CustomerName":"Eqaavq-col Fpcysfptp","AddressLine2":"1221 NH MDFMGDAKSV","AddressLine1":"Wdr Veuniztapbmr 345"],"city":"Amsterdam","BorrowedRatio":"1.4","AdvisorName":"Raju Sen","AdvisorContact":"2123123312","AdviseCost":"1000"]';
expected output :
"payload":{
"name" : "YearlylCostPercentage",
"value":"4.6"
,
"name":"TotalRepayment",
"value":"120000"
apex json
apex json
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
edited Nov 15 '18 at 13:14
Raju Sen
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
asked Nov 14 '18 at 13:45
Raju SenRaju Sen
969
969
1
That's basically JSON abuse. Why do you want/need it in this format?
– sfdcfox
Nov 14 '18 at 13:53
3
Seems like this might be an X-Y problem. What will performing this transformation do for you? What ends up using this JSON? Is there a reason why you can't simply useJSON.deserialize()orJSON.deserializeUntyped()?
– Derek F
Nov 14 '18 at 13:55
yeah, its an abuse, we are trying to connect with one of the services , they want the request body to have this format , so we can't use it as it is, we cant ask them to handle this from their end too.
– Raju Sen
Nov 14 '18 at 14:11
Can we use json.createParser to form this output, iterating every attribute?
– Raju Sen
Nov 14 '18 at 14:16
1
Okay, just realized your JSON expected output is invalid JSON. Are you sure that's correct?
– sfdcfox
Nov 14 '18 at 14:20
|
show 4 more comments
1
That's basically JSON abuse. Why do you want/need it in this format?
– sfdcfox
Nov 14 '18 at 13:53
3
Seems like this might be an X-Y problem. What will performing this transformation do for you? What ends up using this JSON? Is there a reason why you can't simply useJSON.deserialize()orJSON.deserializeUntyped()?
– Derek F
Nov 14 '18 at 13:55
yeah, its an abuse, we are trying to connect with one of the services , they want the request body to have this format , so we can't use it as it is, we cant ask them to handle this from their end too.
– Raju Sen
Nov 14 '18 at 14:11
Can we use json.createParser to form this output, iterating every attribute?
– Raju Sen
Nov 14 '18 at 14:16
1
Okay, just realized your JSON expected output is invalid JSON. Are you sure that's correct?
– sfdcfox
Nov 14 '18 at 14:20
1
1
That's basically JSON abuse. Why do you want/need it in this format?
– sfdcfox
Nov 14 '18 at 13:53
That's basically JSON abuse. Why do you want/need it in this format?
– sfdcfox
Nov 14 '18 at 13:53
3
3
Seems like this might be an X-Y problem. What will performing this transformation do for you? What ends up using this JSON? Is there a reason why you can't simply use
JSON.deserialize() or JSON.deserializeUntyped()?– Derek F
Nov 14 '18 at 13:55
Seems like this might be an X-Y problem. What will performing this transformation do for you? What ends up using this JSON? Is there a reason why you can't simply use
JSON.deserialize() or JSON.deserializeUntyped()?– Derek F
Nov 14 '18 at 13:55
yeah, its an abuse, we are trying to connect with one of the services , they want the request body to have this format , so we can't use it as it is, we cant ask them to handle this from their end too.
– Raju Sen
Nov 14 '18 at 14:11
yeah, its an abuse, we are trying to connect with one of the services , they want the request body to have this format , so we can't use it as it is, we cant ask them to handle this from their end too.
– Raju Sen
Nov 14 '18 at 14:11
Can we use json.createParser to form this output, iterating every attribute?
– Raju Sen
Nov 14 '18 at 14:16
Can we use json.createParser to form this output, iterating every attribute?
– Raju Sen
Nov 14 '18 at 14:16
1
1
Okay, just realized your JSON expected output is invalid JSON. Are you sure that's correct?
– sfdcfox
Nov 14 '18 at 14:20
Okay, just realized your JSON expected output is invalid JSON. Are you sure that's correct?
– sfdcfox
Nov 14 '18 at 14:20
|
show 4 more comments
1 Answer
1
active
oldest
votes
4
JSON.deserializeUntyped is your friend here:
Map<String, Object> jsonParseSource = JSON.deserializeUntyped(jsonBody);
List<Map<String, String>> payload = new List<Map<String, String>>();
Map<String, Object> payloadBody = (Map<String, Object>)jsonParseSource.get('payload');
for(String key: payloadBody.keyset())
payload.add(new Map<String, String> 'name' => key, 'value' => (String)payloadBody.get(key) );
String jsonResult = JSON.serialize(new Map<String, List<Map<String, String>>>
'payload' => payload
);
This results in something like:
"payload": [
"name": "fieldname1", "value": "fieldvalue1" ,
"name": "fieldname2", "value": "fieldvalue2" ]
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
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4
JSON.deserializeUntyped is your friend here:
Map<String, Object> jsonParseSource = JSON.deserializeUntyped(jsonBody);
List<Map<String, String>> payload = new List<Map<String, String>>();
Map<String, Object> payloadBody = (Map<String, Object>)jsonParseSource.get('payload');
for(String key: payloadBody.keyset())
payload.add(new Map<String, String> 'name' => key, 'value' => (String)payloadBody.get(key) );
String jsonResult = JSON.serialize(new Map<String, List<Map<String, String>>>
'payload' => payload
);
This results in something like:
"payload": [
"name": "fieldname1", "value": "fieldvalue1" ,
"name": "fieldname2", "value": "fieldvalue2" ]
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
add a comment |
4
JSON.deserializeUntyped is your friend here:
Map<String, Object> jsonParseSource = JSON.deserializeUntyped(jsonBody);
List<Map<String, String>> payload = new List<Map<String, String>>();
Map<String, Object> payloadBody = (Map<String, Object>)jsonParseSource.get('payload');
for(String key: payloadBody.keyset())
payload.add(new Map<String, String> 'name' => key, 'value' => (String)payloadBody.get(key) );
String jsonResult = JSON.serialize(new Map<String, List<Map<String, String>>>
'payload' => payload
);
This results in something like:
"payload": [
"name": "fieldname1", "value": "fieldvalue1" ,
"name": "fieldname2", "value": "fieldvalue2" ]
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
add a comment |
4
4
4
JSON.deserializeUntyped is your friend here:
Map<String, Object> jsonParseSource = JSON.deserializeUntyped(jsonBody);
List<Map<String, String>> payload = new List<Map<String, String>>();
Map<String, Object> payloadBody = (Map<String, Object>)jsonParseSource.get('payload');
for(String key: payloadBody.keyset())
payload.add(new Map<String, String> 'name' => key, 'value' => (String)payloadBody.get(key) );
String jsonResult = JSON.serialize(new Map<String, List<Map<String, String>>>
'payload' => payload
);
This results in something like:
"payload": [
"name": "fieldname1", "value": "fieldvalue1" ,
"name": "fieldname2", "value": "fieldvalue2" ]
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
JSON.deserializeUntyped is your friend here:
Map<String, Object> jsonParseSource = JSON.deserializeUntyped(jsonBody);
List<Map<String, String>> payload = new List<Map<String, String>>();
Map<String, Object> payloadBody = (Map<String, Object>)jsonParseSource.get('payload');
for(String key: payloadBody.keyset())
payload.add(new Map<String, String> 'name' => key, 'value' => (String)payloadBody.get(key) );
String jsonResult = JSON.serialize(new Map<String, List<Map<String, String>>>
'payload' => payload
);
This results in something like:
"payload": [
"name": "fieldname1", "value": "fieldvalue1" ,
"name": "fieldname2", "value": "fieldvalue2" ]
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
answered Nov 14 '18 at 14:22
sfdcfoxsfdcfox
256k11201441
256k11201441
add a comment |
add a comment |
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1
That's basically JSON abuse. Why do you want/need it in this format?
– sfdcfox
Nov 14 '18 at 13:53
3
Seems like this might be an X-Y problem. What will performing this transformation do for you? What ends up using this JSON? Is there a reason why you can't simply use
JSON.deserialize()orJSON.deserializeUntyped()?– Derek F
Nov 14 '18 at 13:55
yeah, its an abuse, we are trying to connect with one of the services , they want the request body to have this format , so we can't use it as it is, we cant ask them to handle this from their end too.
– Raju Sen
Nov 14 '18 at 14:11
Can we use json.createParser to form this output, iterating every attribute?
– Raju Sen
Nov 14 '18 at 14:16
1
Okay, just realized your JSON expected output is invalid JSON. Are you sure that's correct?
– sfdcfox
Nov 14 '18 at 14:20