Can Json.NET (Schema) filter JSON to a specified schema?
Can I use JSON.NET (or JSON.NET Schema) to filter out additional properties without going via a concrete class (model)?
For example, if my schema is:
"properties":
"levelTwo":
"properties":
"TwoVar1":
"type": "string"
,
"TwoVar2":
"type": "integer"
,
"type": "object"
,
"type": "object"
And the JSON to filter looks like this:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5,
"TwoVar3": 6
,
"OneVar1": "bar",
"OneVar2": 7
I would like the output JSON to look like:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5
I don't want to go via a class to do this as I need a generic solution.
json.net jsonschema
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
add a comment |
Can I use JSON.NET (or JSON.NET Schema) to filter out additional properties without going via a concrete class (model)?
For example, if my schema is:
"properties":
"levelTwo":
"properties":
"TwoVar1":
"type": "string"
,
"TwoVar2":
"type": "integer"
,
"type": "object"
,
"type": "object"
And the JSON to filter looks like this:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5,
"TwoVar3": 6
,
"OneVar1": "bar",
"OneVar2": 7
I would like the output JSON to look like:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5
I don't want to go via a class to do this as I need a generic solution.
json.net jsonschema
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
2
JSON Schema is for validation, not filtering. Sorry.
– Relequestual
Nov 19 '18 at 9:19
add a comment |
Can I use JSON.NET (or JSON.NET Schema) to filter out additional properties without going via a concrete class (model)?
For example, if my schema is:
"properties":
"levelTwo":
"properties":
"TwoVar1":
"type": "string"
,
"TwoVar2":
"type": "integer"
,
"type": "object"
,
"type": "object"
And the JSON to filter looks like this:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5,
"TwoVar3": 6
,
"OneVar1": "bar",
"OneVar2": 7
I would like the output JSON to look like:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5
I don't want to go via a class to do this as I need a generic solution.
json.net jsonschema
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
Can I use JSON.NET (or JSON.NET Schema) to filter out additional properties without going via a concrete class (model)?
For example, if my schema is:
"properties":
"levelTwo":
"properties":
"TwoVar1":
"type": "string"
,
"TwoVar2":
"type": "integer"
,
"type": "object"
,
"type": "object"
And the JSON to filter looks like this:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5,
"TwoVar3": 6
,
"OneVar1": "bar",
"OneVar2": 7
I would like the output JSON to look like:
"levelTwo":
"TwoVar1": "foo",
"TwoVar2": 5
I don't want to go via a class to do this as I need a generic solution.
json.net jsonschema
json.net jsonschema
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
asked Nov 13 '18 at 14:05
Jason SteeleJason Steele
94321837
94321837
2
JSON Schema is for validation, not filtering. Sorry.
– Relequestual
Nov 19 '18 at 9:19
add a comment |
2
JSON Schema is for validation, not filtering. Sorry.
– Relequestual
Nov 19 '18 at 9:19
2
2
JSON Schema is for validation, not filtering. Sorry.
– Relequestual
Nov 19 '18 at 9:19
JSON Schema is for validation, not filtering. Sorry.
– Relequestual
Nov 19 '18 at 9:19
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53282797%2fcan-json-net-schema-filter-json-to-a-specified-schema%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53282797%2fcan-json-net-schema-filter-json-to-a-specified-schema%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
JSON Schema is for validation, not filtering. Sorry.
– Relequestual
Nov 19 '18 at 9:19