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I am trying to make a function that changes the cout and the cin without copy pasting the code but when I try to use it, it always input 0

void enterdata(string data, int data2) // Inputing datas

 cout << "Please Enter your ";
 cout << data.c_str() << endl;
 cin >> data2;

void input1() // Saving/Creating New

 system("cls");
 enterdata("Mobile Number", number);
 cout << "Your number is " << number << endl;

Your int data2 variable is a variable that's local to enterdata. It will be destroyed once the function returns.

If you want to change the passed-in variable you want to take in a reference to the passed argument:

void enterdata(string data, int& data2)

You must pass the value as reference when calling enterdata(). This is because you are expecting the value to change and then use that value later from the calling function. Passing as reference will allow you to use the variable with changed value. Not doing so will result in some default or garbage value in the variable.

So your code should change like this:

void enterdata(string data, int& data2) // Inputing datas <-- note change here

 cout << "Please Enter your ";
 cout << data.c_str() << endl;
 cin >> data2;

void input1() // Saving/Creating New

 system("cls");
 enterdata("Mobile Number", number);
 cout << "Your number is " << number << endl;

There are some recomendations to change data2 to a reference or pointer. But there is a second, simpler method. Just return the value

int enterdata(string data) // Inputing datas

 cout << "Please Enter your ";
 cout << data.c_str() << endl;
 int data2;
 cin >> data2;
 return data2;

void input1() // Saving/Creating New

 system("cls");
 int number = enterdata("Mobile Number");
 cout << "Your number is " << number << endl;