Odtnhj

Is this possible?

Here is an example:

#include <stdio.h>
#include <stdlib.h>

char testString="blunt"

#define shellscript1 "
#/bin/bash n
printf "nHi! The passed value is: $1n" n
"

int main()

 system(shellscript1);

 return 0;

Now I would like to pass a value from testString to shellscript1 without having to reserve to making a temporary external script.

I've been bashing my head, and I couldn't figure out how to do it. Does anyone have any ideas?

Using the environment is possibly the simplest way to achieve it.

#include <stdio.h>
#include <stdlib.h>

char testString="blunt";
#define shellscript1 "bash -c 'printf "nHi! The passed value is: $testStringn"'"
int main()

 if(0>setenv("testString",testString,1)) return EXIT_FAILURE;
 if(0!=system(shellscript1)) return EXIT_FAILURE;
 return 0;

There are other ways, like generating the system argument in a buffer (e.g., with sprintf) or not using system.

system treats its argument like a a string to come after "/bin/sh", "-c". In my answer to using system() with command line arguments in C I coded up a simple my_system alternative that takes the arguments as a string array.

With it, you can do:

#define shellscript1 "printf "nHi! The passed value is: $1n" n"
char testString="blunt";
int main()

 if(0!=my_system("bash", (char*)"bash", "-c", shellscript1, "--", testString,0)) return EXIT_FAILURE;
 return 0;