How to convert the below text string into a date type using SQL Server 2016









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ActivateDate ShipDate Month Month_Length Day-2c Day-2c_Length YEAR-201x SHIPDateConcatenate ActivateDateConcatenate
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
10/12/2018 14:45 10/16/2018 12:00:00 AM 10 2 16 2 2018 10-16-2018 10-12-2018


The two columns [ActivateDate] and [ShipDate] datatype is listed below; however each time I try to use convert() or cast() to a date type, a conversion error occurs.



SELECT
[ActivateDate], -- '10/12/2018 14:45' nvarchar(100)
[ShipDate], -- '6/12/2018 12:00:00 AM' nvarchar(100)
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2) as 'Month',
LEN(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)) as 'Month_Length',
REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','') as 'Day-2c',
LEN(REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')) as 'Day-2c_Length',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'YEAR-201x',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'SHIPDateConcatenate',
SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/201', iedimpr.[ActivateDate])+1,4) as 'ActivateDateConcatenate'









share|improve this question



















  • 2




    6/12/2018 - Is it December 6th or Jun 12th? Same question for 6-12-2018. Also, why are you storing dates as strings? Store dates as date and dates + times as datetime2.
    – Zohar Peled
    Nov 11 at 8:20











  • Good Morning, That is my point. The original data is nvarchar(100) and want to convert it into a date. I initially tried convert(date,[shipdate]) and convert(nvarchar(10),[shipdate],102) but neither seemed to work. In the interium, I tried to at least separate the number as a workaround to convert to a date.
    – TMilzSr
    Nov 12 at 11:58














up vote
-2
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ActivateDate ShipDate Month Month_Length Day-2c Day-2c_Length YEAR-201x SHIPDateConcatenate ActivateDateConcatenate
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
10/12/2018 14:45 10/16/2018 12:00:00 AM 10 2 16 2 2018 10-16-2018 10-12-2018


The two columns [ActivateDate] and [ShipDate] datatype is listed below; however each time I try to use convert() or cast() to a date type, a conversion error occurs.



SELECT
[ActivateDate], -- '10/12/2018 14:45' nvarchar(100)
[ShipDate], -- '6/12/2018 12:00:00 AM' nvarchar(100)
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2) as 'Month',
LEN(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)) as 'Month_Length',
REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','') as 'Day-2c',
LEN(REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')) as 'Day-2c_Length',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'YEAR-201x',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'SHIPDateConcatenate',
SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/201', iedimpr.[ActivateDate])+1,4) as 'ActivateDateConcatenate'









share|improve this question



















  • 2




    6/12/2018 - Is it December 6th or Jun 12th? Same question for 6-12-2018. Also, why are you storing dates as strings? Store dates as date and dates + times as datetime2.
    – Zohar Peled
    Nov 11 at 8:20











  • Good Morning, That is my point. The original data is nvarchar(100) and want to convert it into a date. I initially tried convert(date,[shipdate]) and convert(nvarchar(10),[shipdate],102) but neither seemed to work. In the interium, I tried to at least separate the number as a workaround to convert to a date.
    – TMilzSr
    Nov 12 at 11:58












up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











ActivateDate ShipDate Month Month_Length Day-2c Day-2c_Length YEAR-201x SHIPDateConcatenate ActivateDateConcatenate
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
10/12/2018 14:45 10/16/2018 12:00:00 AM 10 2 16 2 2018 10-16-2018 10-12-2018


The two columns [ActivateDate] and [ShipDate] datatype is listed below; however each time I try to use convert() or cast() to a date type, a conversion error occurs.



SELECT
[ActivateDate], -- '10/12/2018 14:45' nvarchar(100)
[ShipDate], -- '6/12/2018 12:00:00 AM' nvarchar(100)
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2) as 'Month',
LEN(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)) as 'Month_Length',
REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','') as 'Day-2c',
LEN(REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')) as 'Day-2c_Length',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'YEAR-201x',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'SHIPDateConcatenate',
SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/201', iedimpr.[ActivateDate])+1,4) as 'ActivateDateConcatenate'









share|improve this question















ActivateDate ShipDate Month Month_Length Day-2c Day-2c_Length YEAR-201x SHIPDateConcatenate ActivateDateConcatenate
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
NULL 6/12/2018 12:00:00 AM 6 1 12 2 2018 6-12-2018 NULL
10/12/2018 14:45 10/16/2018 12:00:00 AM 10 2 16 2 2018 10-16-2018 10-12-2018


The two columns [ActivateDate] and [ShipDate] datatype is listed below; however each time I try to use convert() or cast() to a date type, a conversion error occurs.



SELECT
[ActivateDate], -- '10/12/2018 14:45' nvarchar(100)
[ShipDate], -- '6/12/2018 12:00:00 AM' nvarchar(100)
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2) as 'Month',
LEN(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)) as 'Month_Length',
REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','') as 'Day-2c',
LEN(REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')) as 'Day-2c_Length',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'YEAR-201x',
SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/', iedimpr.[ShipDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ShipDate],CHARINDEX('/201', iedimpr.[ShipDate])+1,4) as 'SHIPDateConcatenate',
SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])-2,2)
+'-'+REPLACE(SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/', iedimpr.[ActivateDate])+1,2),'/','')
+'-'+SUBSTRING(iedimpr.[ActivateDate],CHARINDEX('/201', iedimpr.[ActivateDate])+1,4) as 'ActivateDateConcatenate'






sql string date sql-server-2016






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edited Nov 12 at 13:32









Zohar Peled

51.4k73172




51.4k73172










asked Nov 11 at 4:17









TMilzSr

72




72







  • 2




    6/12/2018 - Is it December 6th or Jun 12th? Same question for 6-12-2018. Also, why are you storing dates as strings? Store dates as date and dates + times as datetime2.
    – Zohar Peled
    Nov 11 at 8:20











  • Good Morning, That is my point. The original data is nvarchar(100) and want to convert it into a date. I initially tried convert(date,[shipdate]) and convert(nvarchar(10),[shipdate],102) but neither seemed to work. In the interium, I tried to at least separate the number as a workaround to convert to a date.
    – TMilzSr
    Nov 12 at 11:58












  • 2




    6/12/2018 - Is it December 6th or Jun 12th? Same question for 6-12-2018. Also, why are you storing dates as strings? Store dates as date and dates + times as datetime2.
    – Zohar Peled
    Nov 11 at 8:20











  • Good Morning, That is my point. The original data is nvarchar(100) and want to convert it into a date. I initially tried convert(date,[shipdate]) and convert(nvarchar(10),[shipdate],102) but neither seemed to work. In the interium, I tried to at least separate the number as a workaround to convert to a date.
    – TMilzSr
    Nov 12 at 11:58







2




2




6/12/2018 - Is it December 6th or Jun 12th? Same question for 6-12-2018. Also, why are you storing dates as strings? Store dates as date and dates + times as datetime2.
– Zohar Peled
Nov 11 at 8:20





6/12/2018 - Is it December 6th or Jun 12th? Same question for 6-12-2018. Also, why are you storing dates as strings? Store dates as date and dates + times as datetime2.
– Zohar Peled
Nov 11 at 8:20













Good Morning, That is my point. The original data is nvarchar(100) and want to convert it into a date. I initially tried convert(date,[shipdate]) and convert(nvarchar(10),[shipdate],102) but neither seemed to work. In the interium, I tried to at least separate the number as a workaround to convert to a date.
– TMilzSr
Nov 12 at 11:58




Good Morning, That is my point. The original data is nvarchar(100) and want to convert it into a date. I initially tried convert(date,[shipdate]) and convert(nvarchar(10),[shipdate],102) but neither seemed to work. In the interium, I tried to at least separate the number as a workaround to convert to a date.
– TMilzSr
Nov 12 at 11:58












1 Answer
1






active

oldest

votes

















up vote
0
down vote













After reading the question again I've noticed the sample data is ill-formatted, so I've edited it. During this edit I found that you are using american style (mm/dd/yyyy) for your string representation of dates.



To convert a valid string representation of DateTime with this format into date, you need to use 101 as the style parameter in the convert method.

However, I highly recommend using Try_convert instead of Convert, since it will simply return null when the value can't be converted instead of raising an error.



That being said, here is an example:



First, create and populate sample data(Please save us this step in your future questions):



DECLARE @T AS TABLE
(
ActivateDate nvarchar(100),
ShipDate nvarchar(100)
)

INSERT INTO @T(ActivateDate, ShipDate) VALUES
(NULL, '6/12/2018 12:00:00 AM'),
('10/12/2018 14:45', '10/16/2018 12:00:00 AM'),
('20/14/2018 14:45', '10/16/2018 12:00:00 AM'), -- invalid ActivateDate
('2/4/2018 14:45', '10/16/ZOIB 12:00:00 AM') -- invalid ShipDate


The query:



SELECT ActivateDate, 
ShipDate,
TRY_CONVERT(datetime, ActivateDate, 101) As DateActiveDate,
TRY_CONVERT(datetime, ShipDate, 101) As DateShipDate
FROM @T


Results:



ActivateDate ShipDate DateActiveDate DateShipDate
NULL 6/12/2018 12:00:00 AM NULL 12.06.2018 00:00:00
10/12/2018 14:45 10/16/2018 12:00:00 AM 12.10.2018 14:45:00 16.10.2018 00:00:00
20/14/2018 14:45 10/16/2018 12:00:00 AM NULL 16.10.2018 00:00:00
2/4/2018 14:45 10/16/ZOIB 12:00:00 AM 04.02.2018 14:45:00 NULL


If you only need Date (without the time part), simply use try_convert(date, ...) instead of try_convert(datetime, ...).






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    up vote
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    down vote













    After reading the question again I've noticed the sample data is ill-formatted, so I've edited it. During this edit I found that you are using american style (mm/dd/yyyy) for your string representation of dates.



    To convert a valid string representation of DateTime with this format into date, you need to use 101 as the style parameter in the convert method.

    However, I highly recommend using Try_convert instead of Convert, since it will simply return null when the value can't be converted instead of raising an error.



    That being said, here is an example:



    First, create and populate sample data(Please save us this step in your future questions):



    DECLARE @T AS TABLE
    (
    ActivateDate nvarchar(100),
    ShipDate nvarchar(100)
    )

    INSERT INTO @T(ActivateDate, ShipDate) VALUES
    (NULL, '6/12/2018 12:00:00 AM'),
    ('10/12/2018 14:45', '10/16/2018 12:00:00 AM'),
    ('20/14/2018 14:45', '10/16/2018 12:00:00 AM'), -- invalid ActivateDate
    ('2/4/2018 14:45', '10/16/ZOIB 12:00:00 AM') -- invalid ShipDate


    The query:



    SELECT ActivateDate, 
    ShipDate,
    TRY_CONVERT(datetime, ActivateDate, 101) As DateActiveDate,
    TRY_CONVERT(datetime, ShipDate, 101) As DateShipDate
    FROM @T


    Results:



    ActivateDate ShipDate DateActiveDate DateShipDate
    NULL 6/12/2018 12:00:00 AM NULL 12.06.2018 00:00:00
    10/12/2018 14:45 10/16/2018 12:00:00 AM 12.10.2018 14:45:00 16.10.2018 00:00:00
    20/14/2018 14:45 10/16/2018 12:00:00 AM NULL 16.10.2018 00:00:00
    2/4/2018 14:45 10/16/ZOIB 12:00:00 AM 04.02.2018 14:45:00 NULL


    If you only need Date (without the time part), simply use try_convert(date, ...) instead of try_convert(datetime, ...).






    share|improve this answer
























      up vote
      0
      down vote













      After reading the question again I've noticed the sample data is ill-formatted, so I've edited it. During this edit I found that you are using american style (mm/dd/yyyy) for your string representation of dates.



      To convert a valid string representation of DateTime with this format into date, you need to use 101 as the style parameter in the convert method.

      However, I highly recommend using Try_convert instead of Convert, since it will simply return null when the value can't be converted instead of raising an error.



      That being said, here is an example:



      First, create and populate sample data(Please save us this step in your future questions):



      DECLARE @T AS TABLE
      (
      ActivateDate nvarchar(100),
      ShipDate nvarchar(100)
      )

      INSERT INTO @T(ActivateDate, ShipDate) VALUES
      (NULL, '6/12/2018 12:00:00 AM'),
      ('10/12/2018 14:45', '10/16/2018 12:00:00 AM'),
      ('20/14/2018 14:45', '10/16/2018 12:00:00 AM'), -- invalid ActivateDate
      ('2/4/2018 14:45', '10/16/ZOIB 12:00:00 AM') -- invalid ShipDate


      The query:



      SELECT ActivateDate, 
      ShipDate,
      TRY_CONVERT(datetime, ActivateDate, 101) As DateActiveDate,
      TRY_CONVERT(datetime, ShipDate, 101) As DateShipDate
      FROM @T


      Results:



      ActivateDate ShipDate DateActiveDate DateShipDate
      NULL 6/12/2018 12:00:00 AM NULL 12.06.2018 00:00:00
      10/12/2018 14:45 10/16/2018 12:00:00 AM 12.10.2018 14:45:00 16.10.2018 00:00:00
      20/14/2018 14:45 10/16/2018 12:00:00 AM NULL 16.10.2018 00:00:00
      2/4/2018 14:45 10/16/ZOIB 12:00:00 AM 04.02.2018 14:45:00 NULL


      If you only need Date (without the time part), simply use try_convert(date, ...) instead of try_convert(datetime, ...).






      share|improve this answer






















        up vote
        0
        down vote










        up vote
        0
        down vote









        After reading the question again I've noticed the sample data is ill-formatted, so I've edited it. During this edit I found that you are using american style (mm/dd/yyyy) for your string representation of dates.



        To convert a valid string representation of DateTime with this format into date, you need to use 101 as the style parameter in the convert method.

        However, I highly recommend using Try_convert instead of Convert, since it will simply return null when the value can't be converted instead of raising an error.



        That being said, here is an example:



        First, create and populate sample data(Please save us this step in your future questions):



        DECLARE @T AS TABLE
        (
        ActivateDate nvarchar(100),
        ShipDate nvarchar(100)
        )

        INSERT INTO @T(ActivateDate, ShipDate) VALUES
        (NULL, '6/12/2018 12:00:00 AM'),
        ('10/12/2018 14:45', '10/16/2018 12:00:00 AM'),
        ('20/14/2018 14:45', '10/16/2018 12:00:00 AM'), -- invalid ActivateDate
        ('2/4/2018 14:45', '10/16/ZOIB 12:00:00 AM') -- invalid ShipDate


        The query:



        SELECT ActivateDate, 
        ShipDate,
        TRY_CONVERT(datetime, ActivateDate, 101) As DateActiveDate,
        TRY_CONVERT(datetime, ShipDate, 101) As DateShipDate
        FROM @T


        Results:



        ActivateDate ShipDate DateActiveDate DateShipDate
        NULL 6/12/2018 12:00:00 AM NULL 12.06.2018 00:00:00
        10/12/2018 14:45 10/16/2018 12:00:00 AM 12.10.2018 14:45:00 16.10.2018 00:00:00
        20/14/2018 14:45 10/16/2018 12:00:00 AM NULL 16.10.2018 00:00:00
        2/4/2018 14:45 10/16/ZOIB 12:00:00 AM 04.02.2018 14:45:00 NULL


        If you only need Date (without the time part), simply use try_convert(date, ...) instead of try_convert(datetime, ...).






        share|improve this answer












        After reading the question again I've noticed the sample data is ill-formatted, so I've edited it. During this edit I found that you are using american style (mm/dd/yyyy) for your string representation of dates.



        To convert a valid string representation of DateTime with this format into date, you need to use 101 as the style parameter in the convert method.

        However, I highly recommend using Try_convert instead of Convert, since it will simply return null when the value can't be converted instead of raising an error.



        That being said, here is an example:



        First, create and populate sample data(Please save us this step in your future questions):



        DECLARE @T AS TABLE
        (
        ActivateDate nvarchar(100),
        ShipDate nvarchar(100)
        )

        INSERT INTO @T(ActivateDate, ShipDate) VALUES
        (NULL, '6/12/2018 12:00:00 AM'),
        ('10/12/2018 14:45', '10/16/2018 12:00:00 AM'),
        ('20/14/2018 14:45', '10/16/2018 12:00:00 AM'), -- invalid ActivateDate
        ('2/4/2018 14:45', '10/16/ZOIB 12:00:00 AM') -- invalid ShipDate


        The query:



        SELECT ActivateDate, 
        ShipDate,
        TRY_CONVERT(datetime, ActivateDate, 101) As DateActiveDate,
        TRY_CONVERT(datetime, ShipDate, 101) As DateShipDate
        FROM @T


        Results:



        ActivateDate ShipDate DateActiveDate DateShipDate
        NULL 6/12/2018 12:00:00 AM NULL 12.06.2018 00:00:00
        10/12/2018 14:45 10/16/2018 12:00:00 AM 12.10.2018 14:45:00 16.10.2018 00:00:00
        20/14/2018 14:45 10/16/2018 12:00:00 AM NULL 16.10.2018 00:00:00
        2/4/2018 14:45 10/16/ZOIB 12:00:00 AM 04.02.2018 14:45:00 NULL


        If you only need Date (without the time part), simply use try_convert(date, ...) instead of try_convert(datetime, ...).







        share|improve this answer












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        share|improve this answer










        answered Nov 12 at 13:54









        Zohar Peled

        51.4k73172




        51.4k73172



























             

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