How do the instance variables effect the values of my constructors here?










0















I am working through a java exercise and am somewhat confused what the new values of the last 4 lines of code are.



public class Snake 
public Snake x = null;
public Snake y = null;

public static void main(String args)
Snake a = new Snake();
Snake b = new Snake();
a.x = a;
b.x = a.x;
b.y = b.x;
a.y = b.y.x;











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  • You just have an object with a property that points to the object itself... and that's a little like the beginning of infinity :-)

    – ernest_k
    Nov 13 '18 at 17:09











  • By the end both X and Y fields of A and B are equal to A. Whoever authored this exercise is an idiot. It's like trying to teach someone English with "how much wood would a woodchuck chuck"

    – Michael
    Nov 13 '18 at 17:12
















0















I am working through a java exercise and am somewhat confused what the new values of the last 4 lines of code are.



public class Snake 
public Snake x = null;
public Snake y = null;

public static void main(String args)
Snake a = new Snake();
Snake b = new Snake();
a.x = a;
b.x = a.x;
b.y = b.x;
a.y = b.y.x;











share|improve this question
























  • You just have an object with a property that points to the object itself... and that's a little like the beginning of infinity :-)

    – ernest_k
    Nov 13 '18 at 17:09











  • By the end both X and Y fields of A and B are equal to A. Whoever authored this exercise is an idiot. It's like trying to teach someone English with "how much wood would a woodchuck chuck"

    – Michael
    Nov 13 '18 at 17:12














0












0








0








I am working through a java exercise and am somewhat confused what the new values of the last 4 lines of code are.



public class Snake 
public Snake x = null;
public Snake y = null;

public static void main(String args)
Snake a = new Snake();
Snake b = new Snake();
a.x = a;
b.x = a.x;
b.y = b.x;
a.y = b.y.x;











share|improve this question
















I am working through a java exercise and am somewhat confused what the new values of the last 4 lines of code are.



public class Snake 
public Snake x = null;
public Snake y = null;

public static void main(String args)
Snake a = new Snake();
Snake b = new Snake();
a.x = a;
b.x = a.x;
b.y = b.x;
a.y = b.y.x;








java variables constructor






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edited Nov 13 '18 at 17:09









Michael

19.6k83470




19.6k83470










asked Nov 13 '18 at 17:05









Salizmo SqueegeeSalizmo Squeegee

22




22












  • You just have an object with a property that points to the object itself... and that's a little like the beginning of infinity :-)

    – ernest_k
    Nov 13 '18 at 17:09











  • By the end both X and Y fields of A and B are equal to A. Whoever authored this exercise is an idiot. It's like trying to teach someone English with "how much wood would a woodchuck chuck"

    – Michael
    Nov 13 '18 at 17:12


















  • You just have an object with a property that points to the object itself... and that's a little like the beginning of infinity :-)

    – ernest_k
    Nov 13 '18 at 17:09











  • By the end both X and Y fields of A and B are equal to A. Whoever authored this exercise is an idiot. It's like trying to teach someone English with "how much wood would a woodchuck chuck"

    – Michael
    Nov 13 '18 at 17:12

















You just have an object with a property that points to the object itself... and that's a little like the beginning of infinity :-)

– ernest_k
Nov 13 '18 at 17:09





You just have an object with a property that points to the object itself... and that's a little like the beginning of infinity :-)

– ernest_k
Nov 13 '18 at 17:09













By the end both X and Y fields of A and B are equal to A. Whoever authored this exercise is an idiot. It's like trying to teach someone English with "how much wood would a woodchuck chuck"

– Michael
Nov 13 '18 at 17:12






By the end both X and Y fields of A and B are equal to A. Whoever authored this exercise is an idiot. It's like trying to teach someone English with "how much wood would a woodchuck chuck"

– Michael
Nov 13 '18 at 17:12













2 Answers
2






active

oldest

votes


















1














Then you understood that a and b are two snakes. But they are really references to two different snakes.



a.x = a : means make a.x refer to snake referred by a.



b.x = a.x : means make b.x refer to snake referred by a.x (so the same as a).



b.y = b.x : means make b.y refer to snake referred by b.x (so the same as a).



a.y = b.y.x: means make a.y refer to snake referred by b.y.x, as b.y refers to a, this refers to a.x which is the same as a.






share|improve this answer






























    0














    This is how it works:



    a.x = a;


    the x Snake object (property) of the a Snake object becomes a reference (points) to the a Snake object itself.



    b.x = a.x;


    the x Snake object (property) of the b Snake object becomes a reference (points) to the a.x Snake object which previously was set to refer to the a Snake object.
    So this b.x also becomes a reference (points) to the a Snake object .



    b.y = b.x;


    the y Snake object (property) of the b Snake object becomes a reference (points) to the b.x Snake object which previously was set to refer to the a Snake object.
    So this b.y also becomes a reference (points) to the a Snake object .



    a.y = b.y.x;


    the y Snake object (property) of the a Snake object becomes a reference (points) to the b.y.x Snake object and since b.y was previously set to a it is equivalent to a.x which previously was set to refer to the a Snake object.
    So this a.y also becomes a reference (points) to the a Snake object .


    Finally: all the left parts of the assignments refer (point) to a.






    share|improve this answer






















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Then you understood that a and b are two snakes. But they are really references to two different snakes.



      a.x = a : means make a.x refer to snake referred by a.



      b.x = a.x : means make b.x refer to snake referred by a.x (so the same as a).



      b.y = b.x : means make b.y refer to snake referred by b.x (so the same as a).



      a.y = b.y.x: means make a.y refer to snake referred by b.y.x, as b.y refers to a, this refers to a.x which is the same as a.






      share|improve this answer



























        1














        Then you understood that a and b are two snakes. But they are really references to two different snakes.



        a.x = a : means make a.x refer to snake referred by a.



        b.x = a.x : means make b.x refer to snake referred by a.x (so the same as a).



        b.y = b.x : means make b.y refer to snake referred by b.x (so the same as a).



        a.y = b.y.x: means make a.y refer to snake referred by b.y.x, as b.y refers to a, this refers to a.x which is the same as a.






        share|improve this answer

























          1












          1








          1







          Then you understood that a and b are two snakes. But they are really references to two different snakes.



          a.x = a : means make a.x refer to snake referred by a.



          b.x = a.x : means make b.x refer to snake referred by a.x (so the same as a).



          b.y = b.x : means make b.y refer to snake referred by b.x (so the same as a).



          a.y = b.y.x: means make a.y refer to snake referred by b.y.x, as b.y refers to a, this refers to a.x which is the same as a.






          share|improve this answer













          Then you understood that a and b are two snakes. But they are really references to two different snakes.



          a.x = a : means make a.x refer to snake referred by a.



          b.x = a.x : means make b.x refer to snake referred by a.x (so the same as a).



          b.y = b.x : means make b.y refer to snake referred by b.x (so the same as a).



          a.y = b.y.x: means make a.y refer to snake referred by b.y.x, as b.y refers to a, this refers to a.x which is the same as a.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 13 '18 at 17:14









          Jean-Baptiste YunèsJean-Baptiste Yunès

          23.2k12652




          23.2k12652























              0














              This is how it works:



              a.x = a;


              the x Snake object (property) of the a Snake object becomes a reference (points) to the a Snake object itself.



              b.x = a.x;


              the x Snake object (property) of the b Snake object becomes a reference (points) to the a.x Snake object which previously was set to refer to the a Snake object.
              So this b.x also becomes a reference (points) to the a Snake object .



              b.y = b.x;


              the y Snake object (property) of the b Snake object becomes a reference (points) to the b.x Snake object which previously was set to refer to the a Snake object.
              So this b.y also becomes a reference (points) to the a Snake object .



              a.y = b.y.x;


              the y Snake object (property) of the a Snake object becomes a reference (points) to the b.y.x Snake object and since b.y was previously set to a it is equivalent to a.x which previously was set to refer to the a Snake object.
              So this a.y also becomes a reference (points) to the a Snake object .


              Finally: all the left parts of the assignments refer (point) to a.






              share|improve this answer



























                0














                This is how it works:



                a.x = a;


                the x Snake object (property) of the a Snake object becomes a reference (points) to the a Snake object itself.



                b.x = a.x;


                the x Snake object (property) of the b Snake object becomes a reference (points) to the a.x Snake object which previously was set to refer to the a Snake object.
                So this b.x also becomes a reference (points) to the a Snake object .



                b.y = b.x;


                the y Snake object (property) of the b Snake object becomes a reference (points) to the b.x Snake object which previously was set to refer to the a Snake object.
                So this b.y also becomes a reference (points) to the a Snake object .



                a.y = b.y.x;


                the y Snake object (property) of the a Snake object becomes a reference (points) to the b.y.x Snake object and since b.y was previously set to a it is equivalent to a.x which previously was set to refer to the a Snake object.
                So this a.y also becomes a reference (points) to the a Snake object .


                Finally: all the left parts of the assignments refer (point) to a.






                share|improve this answer

























                  0












                  0








                  0







                  This is how it works:



                  a.x = a;


                  the x Snake object (property) of the a Snake object becomes a reference (points) to the a Snake object itself.



                  b.x = a.x;


                  the x Snake object (property) of the b Snake object becomes a reference (points) to the a.x Snake object which previously was set to refer to the a Snake object.
                  So this b.x also becomes a reference (points) to the a Snake object .



                  b.y = b.x;


                  the y Snake object (property) of the b Snake object becomes a reference (points) to the b.x Snake object which previously was set to refer to the a Snake object.
                  So this b.y also becomes a reference (points) to the a Snake object .



                  a.y = b.y.x;


                  the y Snake object (property) of the a Snake object becomes a reference (points) to the b.y.x Snake object and since b.y was previously set to a it is equivalent to a.x which previously was set to refer to the a Snake object.
                  So this a.y also becomes a reference (points) to the a Snake object .


                  Finally: all the left parts of the assignments refer (point) to a.






                  share|improve this answer













                  This is how it works:



                  a.x = a;


                  the x Snake object (property) of the a Snake object becomes a reference (points) to the a Snake object itself.



                  b.x = a.x;


                  the x Snake object (property) of the b Snake object becomes a reference (points) to the a.x Snake object which previously was set to refer to the a Snake object.
                  So this b.x also becomes a reference (points) to the a Snake object .



                  b.y = b.x;


                  the y Snake object (property) of the b Snake object becomes a reference (points) to the b.x Snake object which previously was set to refer to the a Snake object.
                  So this b.y also becomes a reference (points) to the a Snake object .



                  a.y = b.y.x;


                  the y Snake object (property) of the a Snake object becomes a reference (points) to the b.y.x Snake object and since b.y was previously set to a it is equivalent to a.x which previously was set to refer to the a Snake object.
                  So this a.y also becomes a reference (points) to the a Snake object .


                  Finally: all the left parts of the assignments refer (point) to a.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 17:26









                  forpasforpas

                  11k2423




                  11k2423



























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