Plotting the sum of series









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I use this code and i don't know what it needs to work for my problem:



 syms x k t
for t=0:10
num=((-1)^k)/k
t1=sin(8*3.1415*k*t)
S1=symsum((num*t1),k,1,2);
x=0.5-((1/3.1415)*S1);
end
Plot(x)




On the x axis I show time and on the y axis I show the function over four periods.



When I try to run the code I get the following error:




Undefined function 'symsum' for input arguments of type 'double'.




Maybe I can't use symsum with my argument type, but is there another function I can use? Sum also didn't work:




Error using sum Dimension argument must be a positive integer scalar within indexing range.











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  • Does N=2 in the equation so that the symsum ranges from 1 to 2?
    – Banghua Zhao
    Nov 11 at 0:52














up vote
0
down vote

favorite












I use this code and i don't know what it needs to work for my problem:



 syms x k t
for t=0:10
num=((-1)^k)/k
t1=sin(8*3.1415*k*t)
S1=symsum((num*t1),k,1,2);
x=0.5-((1/3.1415)*S1);
end
Plot(x)




On the x axis I show time and on the y axis I show the function over four periods.



When I try to run the code I get the following error:




Undefined function 'symsum' for input arguments of type 'double'.




Maybe I can't use symsum with my argument type, but is there another function I can use? Sum also didn't work:




Error using sum Dimension argument must be a positive integer scalar within indexing range.











share|improve this question























  • Does N=2 in the equation so that the symsum ranges from 1 to 2?
    – Banghua Zhao
    Nov 11 at 0:52












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I use this code and i don't know what it needs to work for my problem:



 syms x k t
for t=0:10
num=((-1)^k)/k
t1=sin(8*3.1415*k*t)
S1=symsum((num*t1),k,1,2);
x=0.5-((1/3.1415)*S1);
end
Plot(x)




On the x axis I show time and on the y axis I show the function over four periods.



When I try to run the code I get the following error:




Undefined function 'symsum' for input arguments of type 'double'.




Maybe I can't use symsum with my argument type, but is there another function I can use? Sum also didn't work:




Error using sum Dimension argument must be a positive integer scalar within indexing range.











share|improve this question















I use this code and i don't know what it needs to work for my problem:



 syms x k t
for t=0:10
num=((-1)^k)/k
t1=sin(8*3.1415*k*t)
S1=symsum((num*t1),k,1,2);
x=0.5-((1/3.1415)*S1);
end
Plot(x)




On the x axis I show time and on the y axis I show the function over four periods.



When I try to run the code I get the following error:




Undefined function 'symsum' for input arguments of type 'double'.




Maybe I can't use symsum with my argument type, but is there another function I can use? Sum also didn't work:




Error using sum Dimension argument must be a positive integer scalar within indexing range.








matlab plot matlab-figure matlab-guide






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edited Nov 11 at 10:10









SecretAgentMan

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397110










asked Nov 11 at 0:23









Alex Mihai

32




32











  • Does N=2 in the equation so that the symsum ranges from 1 to 2?
    – Banghua Zhao
    Nov 11 at 0:52
















  • Does N=2 in the equation so that the symsum ranges from 1 to 2?
    – Banghua Zhao
    Nov 11 at 0:52















Does N=2 in the equation so that the symsum ranges from 1 to 2?
– Banghua Zhao
Nov 11 at 0:52




Does N=2 in the equation so that the symsum ranges from 1 to 2?
– Banghua Zhao
Nov 11 at 0:52












1 Answer
1






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oldest

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up vote
0
down vote



accepted










Since you want to plot x(t), you need to use plot(t,x) where t and x are vectors.



Instead of using for t=0:10, just let t=0:10 and calculate the corresponding x.



Also, the symbolic variable is just k.



syms k 
t=0:10;
num=((-1)^k)/k;
t1=sin(8*3.1415*k*t);
S1=symsum((num*t1),k,1,2);
x=0.5-((1/3.1415)*S1);

plot(t,x)


It is noted that if you let t=0:10, then the sin(8*k*pi*t) will always be 0 since t is a vector of the integer from 0 to 10. The result of x(t) will be 5:



Output when t=0:10:
enter image description here



As you can see, the value of x(t) is very close to each other. Theoretically, they should all be 5. But there is some numerical approximation which leads to the small error.



You probably want non-integer t. Here is a output when t=0:0.1:10
enter image description here






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    Since you want to plot x(t), you need to use plot(t,x) where t and x are vectors.



    Instead of using for t=0:10, just let t=0:10 and calculate the corresponding x.



    Also, the symbolic variable is just k.



    syms k 
    t=0:10;
    num=((-1)^k)/k;
    t1=sin(8*3.1415*k*t);
    S1=symsum((num*t1),k,1,2);
    x=0.5-((1/3.1415)*S1);

    plot(t,x)


    It is noted that if you let t=0:10, then the sin(8*k*pi*t) will always be 0 since t is a vector of the integer from 0 to 10. The result of x(t) will be 5:



    Output when t=0:10:
    enter image description here



    As you can see, the value of x(t) is very close to each other. Theoretically, they should all be 5. But there is some numerical approximation which leads to the small error.



    You probably want non-integer t. Here is a output when t=0:0.1:10
    enter image description here






    share|improve this answer
























      up vote
      0
      down vote



      accepted










      Since you want to plot x(t), you need to use plot(t,x) where t and x are vectors.



      Instead of using for t=0:10, just let t=0:10 and calculate the corresponding x.



      Also, the symbolic variable is just k.



      syms k 
      t=0:10;
      num=((-1)^k)/k;
      t1=sin(8*3.1415*k*t);
      S1=symsum((num*t1),k,1,2);
      x=0.5-((1/3.1415)*S1);

      plot(t,x)


      It is noted that if you let t=0:10, then the sin(8*k*pi*t) will always be 0 since t is a vector of the integer from 0 to 10. The result of x(t) will be 5:



      Output when t=0:10:
      enter image description here



      As you can see, the value of x(t) is very close to each other. Theoretically, they should all be 5. But there is some numerical approximation which leads to the small error.



      You probably want non-integer t. Here is a output when t=0:0.1:10
      enter image description here






      share|improve this answer






















        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        Since you want to plot x(t), you need to use plot(t,x) where t and x are vectors.



        Instead of using for t=0:10, just let t=0:10 and calculate the corresponding x.



        Also, the symbolic variable is just k.



        syms k 
        t=0:10;
        num=((-1)^k)/k;
        t1=sin(8*3.1415*k*t);
        S1=symsum((num*t1),k,1,2);
        x=0.5-((1/3.1415)*S1);

        plot(t,x)


        It is noted that if you let t=0:10, then the sin(8*k*pi*t) will always be 0 since t is a vector of the integer from 0 to 10. The result of x(t) will be 5:



        Output when t=0:10:
        enter image description here



        As you can see, the value of x(t) is very close to each other. Theoretically, they should all be 5. But there is some numerical approximation which leads to the small error.



        You probably want non-integer t. Here is a output when t=0:0.1:10
        enter image description here






        share|improve this answer












        Since you want to plot x(t), you need to use plot(t,x) where t and x are vectors.



        Instead of using for t=0:10, just let t=0:10 and calculate the corresponding x.



        Also, the symbolic variable is just k.



        syms k 
        t=0:10;
        num=((-1)^k)/k;
        t1=sin(8*3.1415*k*t);
        S1=symsum((num*t1),k,1,2);
        x=0.5-((1/3.1415)*S1);

        plot(t,x)


        It is noted that if you let t=0:10, then the sin(8*k*pi*t) will always be 0 since t is a vector of the integer from 0 to 10. The result of x(t) will be 5:



        Output when t=0:10:
        enter image description here



        As you can see, the value of x(t) is very close to each other. Theoretically, they should all be 5. But there is some numerical approximation which leads to the small error.



        You probably want non-integer t. Here is a output when t=0:0.1:10
        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 11 at 4:33









        Banghua Zhao

        802217




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