Multiple if search statements in excel?
I am trying to convert text of the month to the number
B2 cell:
BirthMonth_Jan
BirthMonth_Feb
BirthMonth_mar
BirthMonth_Apr
BirthMonth_May
BirthMonth_Jun, ect to december
for example, BirthMonth_Jan will output 1 based on the search of Jan, so i can compare this to another set of numbers
I have this, and tried this, but only works with two if statements, is there anyway i can do this with 12?
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
I get #Value!
If i try this, it also doesn't work
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
the second option only works with two but if i add more it throws an error
excel if-statement statements
add a comment |
I am trying to convert text of the month to the number
B2 cell:
BirthMonth_Jan
BirthMonth_Feb
BirthMonth_mar
BirthMonth_Apr
BirthMonth_May
BirthMonth_Jun, ect to december
for example, BirthMonth_Jan will output 1 based on the search of Jan, so i can compare this to another set of numbers
I have this, and tried this, but only works with two if statements, is there anyway i can do this with 12?
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
I get #Value!
If i try this, it also doesn't work
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
the second option only works with two but if i add more it throws an error
excel if-statement statements
add a comment |
I am trying to convert text of the month to the number
B2 cell:
BirthMonth_Jan
BirthMonth_Feb
BirthMonth_mar
BirthMonth_Apr
BirthMonth_May
BirthMonth_Jun, ect to december
for example, BirthMonth_Jan will output 1 based on the search of Jan, so i can compare this to another set of numbers
I have this, and tried this, but only works with two if statements, is there anyway i can do this with 12?
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
I get #Value!
If i try this, it also doesn't work
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
the second option only works with two but if i add more it throws an error
excel if-statement statements
I am trying to convert text of the month to the number
B2 cell:
BirthMonth_Jan
BirthMonth_Feb
BirthMonth_mar
BirthMonth_Apr
BirthMonth_May
BirthMonth_Jun, ect to december
for example, BirthMonth_Jan will output 1 based on the search of Jan, so i can compare this to another set of numbers
I have this, and tried this, but only works with two if statements, is there anyway i can do this with 12?
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
I get #Value!
If i try this, it also doesn't work
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
the second option only works with two but if i add more it throws an error
excel if-statement statements
excel if-statement statements
asked Nov 15 '18 at 20:18
gbdavidxgbdavidx
1
1
add a comment |
add a comment |
3 Answers
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Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
add a comment |
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
add a comment |
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search
since it is not case-sensitive
Two formula are offered:
Formula 1=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if
statements, each separated by a comma. It is an invalid statement.
However, if the if
statements were nested, then the formula would work. Something along these lines:=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11"))
in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA()
function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP
. My equivalent formula would be:=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2)
,
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2)
to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2))
. This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
add a comment |
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3 Answers
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active
oldest
votes
3 Answers
3
active
oldest
votes
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Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
add a comment |
Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
add a comment |
Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
answered Nov 15 '18 at 20:39
Display nameDisplay name
53416
53416
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
add a comment |
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
Not sure if this would work, forgot to mention i have other text in the field i can't parse out
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
I found this, that may be a solution, if i can get it working, myonlinetraininghub.com/excel-search-string-for-a-list-of-words
– gbdavidx
Nov 15 '18 at 21:03
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
trying to export the birth month only based on search criteria
– gbdavidx
Nov 15 '18 at 21:05
add a comment |
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
add a comment |
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
add a comment |
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
answered Nov 15 '18 at 22:09
pnutspnuts
49.1k764101
49.1k764101
add a comment |
add a comment |
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search
since it is not case-sensitive
Two formula are offered:
Formula 1=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if
statements, each separated by a comma. It is an invalid statement.
However, if the if
statements were nested, then the formula would work. Something along these lines:=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11"))
in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA()
function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP
. My equivalent formula would be:=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2)
,
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2)
to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2))
. This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
add a comment |
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search
since it is not case-sensitive
Two formula are offered:
Formula 1=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if
statements, each separated by a comma. It is an invalid statement.
However, if the if
statements were nested, then the formula would work. Something along these lines:=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11"))
in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA()
function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP
. My equivalent formula would be:=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2)
,
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2)
to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2))
. This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
add a comment |
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search
since it is not case-sensitive
Two formula are offered:
Formula 1=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if
statements, each separated by a comma. It is an invalid statement.
However, if the if
statements were nested, then the formula would work. Something along these lines:=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11"))
in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA()
function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP
. My equivalent formula would be:=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2)
,
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2)
to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2))
. This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search
since it is not case-sensitive
Two formula are offered:
Formula 1=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if
statements, each separated by a comma. It is an invalid statement.
However, if the if
statements were nested, then the formula would work. Something along these lines:=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11"))
in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA()
function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP
. My equivalent formula would be:=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2)
,
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2)
to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2))
. This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
answered Nov 15 '18 at 23:43
TedinozTedinoz
1,27521319
1,27521319
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