different keys with same value in python
I am writing a simple game: "rock paper scissors".
I assigned
1 to "paper",
2 to scissors,
3 to rock.
I wrote the function determining who wins. This function gets two values: the computer's choise and the user's choise.
def winner(computer, user) :
difference = computer - user
dic =
[1,-2] : "computer" ,
[-1,2] : "user",
[0]: "draw"
how can i give difference to dic and recive their value?
python
add a comment |
I am writing a simple game: "rock paper scissors".
I assigned
1 to "paper",
2 to scissors,
3 to rock.
I wrote the function determining who wins. This function gets two values: the computer's choise and the user's choise.
def winner(computer, user) :
difference = computer - user
dic =
[1,-2] : "computer" ,
[-1,2] : "user",
[0]: "draw"
how can i give difference to dic and recive their value?
python
Dictionary keys cannot be of a mutable type, try using a tuple instead of a list. (Edit: VNM, just use 1: "computer", -2: "computer"
– mousetail
Nov 12 at 8:06
Consider this implementation: "if difference mod 3 == 2 then user, if difference mod 3 == 1 then computer else draw. "
– jimifiki
Nov 12 at 8:17
add a comment |
I am writing a simple game: "rock paper scissors".
I assigned
1 to "paper",
2 to scissors,
3 to rock.
I wrote the function determining who wins. This function gets two values: the computer's choise and the user's choise.
def winner(computer, user) :
difference = computer - user
dic =
[1,-2] : "computer" ,
[-1,2] : "user",
[0]: "draw"
how can i give difference to dic and recive their value?
python
I am writing a simple game: "rock paper scissors".
I assigned
1 to "paper",
2 to scissors,
3 to rock.
I wrote the function determining who wins. This function gets two values: the computer's choise and the user's choise.
def winner(computer, user) :
difference = computer - user
dic =
[1,-2] : "computer" ,
[-1,2] : "user",
[0]: "draw"
how can i give difference to dic and recive their value?
python
python
edited Nov 12 at 8:20
jimifiki
3,36511943
3,36511943
asked Nov 12 at 8:04
omid
81
81
Dictionary keys cannot be of a mutable type, try using a tuple instead of a list. (Edit: VNM, just use 1: "computer", -2: "computer"
– mousetail
Nov 12 at 8:06
Consider this implementation: "if difference mod 3 == 2 then user, if difference mod 3 == 1 then computer else draw. "
– jimifiki
Nov 12 at 8:17
add a comment |
Dictionary keys cannot be of a mutable type, try using a tuple instead of a list. (Edit: VNM, just use 1: "computer", -2: "computer"
– mousetail
Nov 12 at 8:06
Consider this implementation: "if difference mod 3 == 2 then user, if difference mod 3 == 1 then computer else draw. "
– jimifiki
Nov 12 at 8:17
Dictionary keys cannot be of a mutable type, try using a tuple instead of a list. (Edit: VNM, just use 1: "computer", -2: "computer"
– mousetail
Nov 12 at 8:06
Dictionary keys cannot be of a mutable type, try using a tuple instead of a list. (Edit: VNM, just use 1: "computer", -2: "computer"
– mousetail
Nov 12 at 8:06
Consider this implementation: "if difference mod 3 == 2 then user, if difference mod 3 == 1 then computer else draw. "
– jimifiki
Nov 12 at 8:17
Consider this implementation: "if difference mod 3 == 2 then user, if difference mod 3 == 1 then computer else draw. "
– jimifiki
Nov 12 at 8:17
add a comment |
2 Answers
2
active
oldest
votes
For your case you might consider to drop the dict entirely:
def winner(computer, user):
difference = (computer - user) % 3
if difference == 2:
return "computer"
elif difference == 1:
return "user"
return "draw"
add a comment |
You can't use multiple keys like that, as you've seen. You could, however, just enter several keys with the same value to the dictionary:
dic =
1 : "computer",
-2 : "computer",
-1 : "user",
2 : "user",
0: "draw"
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
For your case you might consider to drop the dict entirely:
def winner(computer, user):
difference = (computer - user) % 3
if difference == 2:
return "computer"
elif difference == 1:
return "user"
return "draw"
add a comment |
For your case you might consider to drop the dict entirely:
def winner(computer, user):
difference = (computer - user) % 3
if difference == 2:
return "computer"
elif difference == 1:
return "user"
return "draw"
add a comment |
For your case you might consider to drop the dict entirely:
def winner(computer, user):
difference = (computer - user) % 3
if difference == 2:
return "computer"
elif difference == 1:
return "user"
return "draw"
For your case you might consider to drop the dict entirely:
def winner(computer, user):
difference = (computer - user) % 3
if difference == 2:
return "computer"
elif difference == 1:
return "user"
return "draw"
answered Nov 12 at 8:33
jimifiki
3,36511943
3,36511943
add a comment |
add a comment |
You can't use multiple keys like that, as you've seen. You could, however, just enter several keys with the same value to the dictionary:
dic =
1 : "computer",
-2 : "computer",
-1 : "user",
2 : "user",
0: "draw"
add a comment |
You can't use multiple keys like that, as you've seen. You could, however, just enter several keys with the same value to the dictionary:
dic =
1 : "computer",
-2 : "computer",
-1 : "user",
2 : "user",
0: "draw"
add a comment |
You can't use multiple keys like that, as you've seen. You could, however, just enter several keys with the same value to the dictionary:
dic =
1 : "computer",
-2 : "computer",
-1 : "user",
2 : "user",
0: "draw"
You can't use multiple keys like that, as you've seen. You could, however, just enter several keys with the same value to the dictionary:
dic =
1 : "computer",
-2 : "computer",
-1 : "user",
2 : "user",
0: "draw"
answered Nov 12 at 8:10
Mureinik
178k22129198
178k22129198
add a comment |
add a comment |
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Dictionary keys cannot be of a mutable type, try using a tuple instead of a list. (Edit: VNM, just use 1: "computer", -2: "computer"
– mousetail
Nov 12 at 8:06
Consider this implementation: "if difference mod 3 == 2 then user, if difference mod 3 == 1 then computer else draw. "
– jimifiki
Nov 12 at 8:17