How to group by month in Elastic search










0















I am using elastic search version 6.0.0
for group by month, I am using date histogram aggregation.
example which I've tried :



 
"from":0,
"size":2000,
"_source":
"includes":[
"cost",
"date"
],
"excludes":[

],
"aggregations":
"date_hist_agg":
"date_histogram":
"field":"date",
"interval":"month",
"format":"M",
"order":
"_key":"asc"
,
"min_doc_count":1
,
"aggregations":
"cost":
"sum":
"field":"cost"









and as a result i got 1(Jan/January) multiple times.
As I have data of January-2016 ,January-2017 , January-2018 so will return 3 times January. but i Want January only once which contains the sum of All years of January.










share|improve this question




























    0















    I am using elastic search version 6.0.0
    for group by month, I am using date histogram aggregation.
    example which I've tried :



     
    "from":0,
    "size":2000,
    "_source":
    "includes":[
    "cost",
    "date"
    ],
    "excludes":[

    ],
    "aggregations":
    "date_hist_agg":
    "date_histogram":
    "field":"date",
    "interval":"month",
    "format":"M",
    "order":
    "_key":"asc"
    ,
    "min_doc_count":1
    ,
    "aggregations":
    "cost":
    "sum":
    "field":"cost"









    and as a result i got 1(Jan/January) multiple times.
    As I have data of January-2016 ,January-2017 , January-2018 so will return 3 times January. but i Want January only once which contains the sum of All years of January.










    share|improve this question


























      0












      0








      0


      0






      I am using elastic search version 6.0.0
      for group by month, I am using date histogram aggregation.
      example which I've tried :



       
      "from":0,
      "size":2000,
      "_source":
      "includes":[
      "cost",
      "date"
      ],
      "excludes":[

      ],
      "aggregations":
      "date_hist_agg":
      "date_histogram":
      "field":"date",
      "interval":"month",
      "format":"M",
      "order":
      "_key":"asc"
      ,
      "min_doc_count":1
      ,
      "aggregations":
      "cost":
      "sum":
      "field":"cost"









      and as a result i got 1(Jan/January) multiple times.
      As I have data of January-2016 ,January-2017 , January-2018 so will return 3 times January. but i Want January only once which contains the sum of All years of January.










      share|improve this question
















      I am using elastic search version 6.0.0
      for group by month, I am using date histogram aggregation.
      example which I've tried :



       
      "from":0,
      "size":2000,
      "_source":
      "includes":[
      "cost",
      "date"
      ],
      "excludes":[

      ],
      "aggregations":
      "date_hist_agg":
      "date_histogram":
      "field":"date",
      "interval":"month",
      "format":"M",
      "order":
      "_key":"asc"
      ,
      "min_doc_count":1
      ,
      "aggregations":
      "cost":
      "sum":
      "field":"cost"









      and as a result i got 1(Jan/January) multiple times.
      As I have data of January-2016 ,January-2017 , January-2018 so will return 3 times January. but i Want January only once which contains the sum of All years of January.







      elasticsearch elasticsearch-5 elasticsearch-aggregation elasticsearch-6






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 '18 at 13:00







      kavi

















      asked Aug 16 '18 at 8:08









      kavikavi

      5011




      5011






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Instead of using a date_histogram aggregation you could use a terms aggregation with a script that extracts the month from the date.




          "from": 0,
          "size": 2000,
          "_source": "includes": ["cost","date"],"excludes",
          "aggregations":
          "date_hist_agg":
          "terms":
          "script": "doc['date'].date.monthOfYear",
          "order":
          "_key": "asc"
          ,
          "min_doc_count": 1
          ,
          "aggregations":
          "cost":
          "sum":
          "field": "cost"








          Note that using scripting is not optimal, if you know you'll need the month information, just create another field with that information so you can use a simple terms aggregation on it without having to use scripting.






          share|improve this answer























          • Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

            – kavi
            Aug 24 '18 at 6:37











          • @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

            – Val
            Aug 24 '18 at 6:39












          • can you explain why the time_zone feature is not supported?

            – Val
            Aug 29 '18 at 7:43










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Instead of using a date_histogram aggregation you could use a terms aggregation with a script that extracts the month from the date.




          "from": 0,
          "size": 2000,
          "_source": "includes": ["cost","date"],"excludes",
          "aggregations":
          "date_hist_agg":
          "terms":
          "script": "doc['date'].date.monthOfYear",
          "order":
          "_key": "asc"
          ,
          "min_doc_count": 1
          ,
          "aggregations":
          "cost":
          "sum":
          "field": "cost"








          Note that using scripting is not optimal, if you know you'll need the month information, just create another field with that information so you can use a simple terms aggregation on it without having to use scripting.






          share|improve this answer























          • Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

            – kavi
            Aug 24 '18 at 6:37











          • @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

            – Val
            Aug 24 '18 at 6:39












          • can you explain why the time_zone feature is not supported?

            – Val
            Aug 29 '18 at 7:43















          1














          Instead of using a date_histogram aggregation you could use a terms aggregation with a script that extracts the month from the date.




          "from": 0,
          "size": 2000,
          "_source": "includes": ["cost","date"],"excludes",
          "aggregations":
          "date_hist_agg":
          "terms":
          "script": "doc['date'].date.monthOfYear",
          "order":
          "_key": "asc"
          ,
          "min_doc_count": 1
          ,
          "aggregations":
          "cost":
          "sum":
          "field": "cost"








          Note that using scripting is not optimal, if you know you'll need the month information, just create another field with that information so you can use a simple terms aggregation on it without having to use scripting.






          share|improve this answer























          • Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

            – kavi
            Aug 24 '18 at 6:37











          • @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

            – Val
            Aug 24 '18 at 6:39












          • can you explain why the time_zone feature is not supported?

            – Val
            Aug 29 '18 at 7:43













          1












          1








          1







          Instead of using a date_histogram aggregation you could use a terms aggregation with a script that extracts the month from the date.




          "from": 0,
          "size": 2000,
          "_source": "includes": ["cost","date"],"excludes",
          "aggregations":
          "date_hist_agg":
          "terms":
          "script": "doc['date'].date.monthOfYear",
          "order":
          "_key": "asc"
          ,
          "min_doc_count": 1
          ,
          "aggregations":
          "cost":
          "sum":
          "field": "cost"








          Note that using scripting is not optimal, if you know you'll need the month information, just create another field with that information so you can use a simple terms aggregation on it without having to use scripting.






          share|improve this answer













          Instead of using a date_histogram aggregation you could use a terms aggregation with a script that extracts the month from the date.




          "from": 0,
          "size": 2000,
          "_source": "includes": ["cost","date"],"excludes",
          "aggregations":
          "date_hist_agg":
          "terms":
          "script": "doc['date'].date.monthOfYear",
          "order":
          "_key": "asc"
          ,
          "min_doc_count": 1
          ,
          "aggregations":
          "cost":
          "sum":
          "field": "cost"








          Note that using scripting is not optimal, if you know you'll need the month information, just create another field with that information so you can use a simple terms aggregation on it without having to use scripting.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Aug 16 '18 at 8:36









          ValVal

          103k6138173




          103k6138173












          • Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

            – kavi
            Aug 24 '18 at 6:37











          • @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

            – Val
            Aug 24 '18 at 6:39












          • can you explain why the time_zone feature is not supported?

            – Val
            Aug 29 '18 at 7:43

















          • Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

            – kavi
            Aug 24 '18 at 6:37











          • @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

            – Val
            Aug 24 '18 at 6:39












          • can you explain why the time_zone feature is not supported?

            – Val
            Aug 29 '18 at 7:43
















          Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

          – kavi
          Aug 24 '18 at 6:37





          Is there any other way for this ? cause sometimes i got BAD GATEWAY error due to execution of script

          – kavi
          Aug 24 '18 at 6:37













          @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

          – Val
          Aug 24 '18 at 6:39






          @kpatel Yes, I've explained another solution here: stackoverflow.com/questions/37585988/day-of-month-aggregation/…

          – Val
          Aug 24 '18 at 6:39














          can you explain why the time_zone feature is not supported?

          – Val
          Aug 29 '18 at 7:43





          can you explain why the time_zone feature is not supported?

          – Val
          Aug 29 '18 at 7:43

















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